Answer:
Explanation:
We shall apply Ampere's circuital law to find out magnetic field . It is given as follows.
∫B.dl = μ₀ I , B is magnetic field , I is current , μ₀ is permeability .
Radius of the wire r = 1.2 x 10⁻³ m
magnetic field B will be circular in shape around the wire. If B is uniform
∫B.dl = B x 2πr
B x 2πr = μ₀ I
B = μ₀ I / 2πr
= 4π x 10⁻⁷ x 37 /2πx1.2 x 10⁻³
= 10⁻⁷ x 2x37 / 1.2 x 10⁻³
= 61.67 x 10⁻⁴ T
= 62 x 10⁻⁴ T
Answer:
63
Explanation:
You first have to add all the numbers together.
22+72+79+72+70 = 315
You divide the total by the amount of numbers (5)
315/5 = 63
The mean is 63
Because the Earth's axis is not "straight up and down" as we move
around the sun.
So when we're on one side of the sun, the top pole leans slightly toward
the sun. During that time the sun shines more directly on the top half
of the Earth, and less directly on the bottom half. The people on the
top half see the sun higher in the sky, and their weather is warmer,
while the people on the bottom half see the sun lower in the sky, and
their weather is cooler.
Then, when we're on the other side of the sun, the top pole leans slightly
away from the sun. During that time the sun shines more directly on the
bottom half
of the Earth, and less directly on the top half. The people on
the bottom half see the sun higher in the sky, and their weather is warmer,
while the people on the top half see the sun lower in the sky, and their
weather is cooler.
The Earth makes the complete trip around the sun in one year, so the
people on the Earth go through this cycle of higher/lower sun and
warmer/cooler weather every year.
Answer: a
Explanation: because the answer is 1.4444444 and that's the closest
Answer:
6.22²
Explanation:
Given that
Mass of the skydiver, m = 80 kg
Terminal speed of the skydiver, v(f) = 50 m/s
Speed of the skydiver, v(i) = 30 m/s
Acceleration of the skydiver, a = ?
To solve this, we use the formula
W - k v² = ma, where
W = weight of the skydiver
k = constant
v = speed of the skydiver
m = mass of the skydiver
So, if we substitute the values into it we have
W = mg = 80 * 9.8 = 784 N
784 - k 50² = 80 *0
784 - 2500k = 0
784 = 2500k
k = 0.3136
Now, we use this value of k to find the needed acceleration using the same formula at a speed of 30 m/s
784 - 0.3136 * 30² = 80 * a
784 - 0.3136 * 900 = 80a
784 - 282.24 = 80a
497.76 = 80a
a = 497.76 / 80
a = 6.22 m/s²
Thus, we can conclude that the acceleration when the speed of the skydiver is 30 m/s, is 6.22 m/s²
