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nevsk [136]
3 years ago
9

(FIRST TO ANSWER CORRECTLY WILL BE THE BRAINIEST!!!)How will the temperatures of the water in the beakers compare if an equal am

ount of heat is absorbed by both beakers of water? both have an equal amount of water and both have the EXACT same temperature
A.
The temperature of Beaker A's water will remain 75°C,
and the temperature of Beaker B's water will be above 75°C.

B.
The temperatures of both beakers' water will increase by the same amount.

C.
The temperatures of both beakers' water will decrease by the same amount.

D.
The temperature of Beaker B's water will remain 75°C,
and the temperature of Beaker A's water will be above 75°C.
Physics
2 answers:
Tatiana [17]3 years ago
8 0

Answer:

the answer is B. The temperatures of both beakers' water will increase by the same amount.

Explanation:

bulgar [2K]3 years ago
7 0

Answer:

the answer is the temperatures of both beakers' water will increase by the same amount...

Explanation:

I know this because i just did it on study island

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10-kg box is sliding across an ice rink at 10 m/s . A skater exerts a constant force of 10 N against it. How long will it take f
Taya2010 [7]

Answer:

Time, t = 10 seconds

Explanation:

Given the following data;

Mass = 10kg

Force = 10N

Final velocity = 10m/s

Initial velocity = 0m/s

To find the time;

First of all, we would find the acceleration of the box.

Force = mass * acceleration

10 = 10 * acceleration

Acceleration = 10/10 = 1m/s²

Now, we can find the time by using the first equation of motion;

V = U + at

10 = 0 + 1t

10 = t

Time, t = 10 seconds

Therefore, it will take 10 seconds for the box to come to a complete stop.

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According to newton's second law of motion, when an object is acted on by an unbalanced force, how will that object respond?
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a car traveling at 7.0 m/s accelerates uni formally at 2.5 m/s^2 to reach a speed of 12.0 m/s how long does it take for the acce
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A light-rail train going from one station to the next on a straight section of track accelerates from rest at 1.1 m/s2 for 20 s.
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It accelerates from rest at 1.1 m/s^2 for 20s. 

<span>s = at^2/2 </span>
<span>s = (.5)(1.1)(20)^2= 220m </span>

<span>then it travels 1100m </span>

<span>Then it slows down at 2.2m/s^2 until it stops at the station. </span>

<span>Calculate the train's speed: </span>
<span>v = at </span>
<span>v = (1.1)(20) = 22m/s 
</span>
<span>Now, calculate the time to stop: </span>
<span>v = at </span>
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<span>s = t(u+v)/2 </span>
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<span>(A) Total distance = 220 +1100+110 = 1430m </span>

<span>(B) Time = 20 + 1100/22 + 10 = 80s</span>
6 0
4 years ago
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