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nevsk [136]
3 years ago
9

(FIRST TO ANSWER CORRECTLY WILL BE THE BRAINIEST!!!)How will the temperatures of the water in the beakers compare if an equal am

ount of heat is absorbed by both beakers of water? both have an equal amount of water and both have the EXACT same temperature
A.
The temperature of Beaker A's water will remain 75°C,
and the temperature of Beaker B's water will be above 75°C.

B.
The temperatures of both beakers' water will increase by the same amount.

C.
The temperatures of both beakers' water will decrease by the same amount.

D.
The temperature of Beaker B's water will remain 75°C,
and the temperature of Beaker A's water will be above 75°C.
Physics
2 answers:
Tatiana [17]3 years ago
8 0

Answer:

the answer is B. The temperatures of both beakers' water will increase by the same amount.

Explanation:

bulgar [2K]3 years ago
7 0

Answer:

the answer is the temperatures of both beakers' water will increase by the same amount...

Explanation:

I know this because i just did it on study island

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How a suit of armor might be a good analogy for a function of the skeleton system
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How might a suit of armor be a good analogy for a function of the skeletal system?

It's a frame for your body and protects organs and armor protects your body from injury

4 0
3 years ago
Two ships of equal mass are 110 m apart. What is the acceleration of either ship due to the gravitational attraction of the othe
dusya [7]

Answer:

Acceleration of the ship, a=2.14\times 10^{-7}\ m/s^2

Explanation:

It is given that,

Mass of both ships, m=39000\ metric\ tons=39\times 10^6\ kg

Distance between two ships, d = 110 m

The gravitational force between two ships is given by :

F=G\dfrac{m^2}{d^2}

F=6.67\times 10^{-11}\ Nm^2/kg^2\times \dfrac{(39\times 10^6\ kg)^2}{(110\ m)^2}

F = 8.38 N

Let a is the acceleration. Now, using second law of motion as :

a=\dfrac{F}{m}

a=\dfrac{8.38\ N}{39\times 10^6\ kg}

a=2.14\times 10^{-7}\ m/s^2

So, the acceleration of either ship due to the gravitational attraction of the other is 2.14\times 10^{-7}\ m/s^2. Hence, this is the required solution.

7 0
3 years ago
Is The neck is an example of a simple machine in the human body?
tatyana61 [14]
No it's the quite opposite simple
3 0
3 years ago
Read 2 more answers
A small metal ball is suspended from the ceiling by a thread of negligible mass. The ball is then set in motion in a horizontal
Gemiola [76]

Answer:

Time taken, T=2\pi \sqrt{\dfrac{l\ cos\theta}{g}}

Explanation:

It is given that, a small metal ball is suspended from the ceiling by a thread of negligible mass. The ball is then set in motion in a horizontal circle so that the thread’s trajectory describes a cone as shown in attached figure.

From the figure,

The sum of forces in y direction is :

T\ cos\theta-mg=0

T=\dfrac{mg}{cos\theta}

Sum of forces in x direction,

T\ sin\theta=\dfrac{mv^2}{r}

mg\ tan\theta=\dfrac{mv^2}{r}.............(1)

Also, r=l\ sin\theta

Equation (1) becomes :

mg\ tan\theta=\dfrac{mv^2}{l\ sin\theta}

v=\sqrt{gl\ tan\theta.sin\theta}...............(2)

Let t is the time taken for the ball to rotate once around the axis. It is given by :

T=\dfrac{2\pi r}{v}

Put the value of T from equation (2) to the above expression:

T=\dfrac{2\pi r}{\sqrt{gl\ tan\theta.sin\theta}}

T=\dfrac{2\pi l\ sin\theta}{\sqrt{gl\ tan\theta.sin\theta}}

On solving above equation :

T=2\pi \sqrt{\dfrac{l\ cos\theta}{g}}

Hence, this is the required solution.

4 0
3 years ago
Can I get help and an explanation on C?
Diano4ka-milaya [45]

Answer:

1.67 m/s

Explanation:

Momentum is conserved.

Initial momentum = final momentum

(30 kg) (10 m/s) + (35 kg) (-10 m/s) = (30 kg) v + (35 kg) (0 m/s)

300 - 350 = 30v

v = -5/3 m/s

Linus will move at 1.67 m/s in the direction opposite that he started.

6 0
3 years ago
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