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vitfil [10]
3 years ago
10

The magnitude​ R, measured on the Richter​ scale, of an earthquake of intensity I is defined as Requalslog StartFraction Upper I

Over Upper I 0 EndFraction ​, where Upper I 0 is a minimum intensity used for comparison. If the intensity of an earthquake was 10 Superscript 6.08times Upper I0​, what was the magnitude on the Richter​ scale?
Physics
1 answer:
lapo4ka [179]3 years ago
6 0

Answer:

R = 6.8

Explanation:

Given data:

Richter scaleR = log(\frac{I}{I_o})

where R - magnitude of earthquake of Richter scale

I - quake's intensity =  10^{6.8} \times I_o

I_o - minimum intensity earthquake

Plugging all information in the equation to get Richter's scale

R = log(\frac{10^{6.8} \times I_o}{I_o})

R = log(10^{6.8})

R = 6.8

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alina1380 [7]

Answer:

1.758820×10^11(-2.5i-0.8j) m/s^2

Explanation:

From the question, the parameters given are; E=(2.80i+ 5.20j) v/m, a uniform magnetic field,B= 0.400K T, acceleration, a= ??? and velocity vector, v= 11.0i metre per seconds (m/s)...

We can solve this problem using the formula below;

Ma= q[E+V × B] ---------------(1).

Note: q is negative, m= mass of electron.

Making acceleration,a the subject of the formula and substituting the parameters into equation (1);

a= -e/m × (2.5i + 5.2j +11.0i × 0.400K)

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a= e/m × (-2.5i - 0.8j)

e/m= 1.758820×10^11 c/kg

Therefore, slotting in the value of charge to mass(e/m) ratio;

a= 1.7588×10^11×(-2.5i-0.8j) m/s^2

7 0
3 years ago
ALWAYS use significant figure rules. Remember that these rules apply to all numbers that are measurements.
vekshin1

Answer:

The answer is 500

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6 0
2 years ago
The auto in the sketch moves forward as the brakes are applied. A bystander says that during the interval of braking, the auto's
Ivan

Answer:

The statement is true: velocity and acceleration have opposite directions in the interval of braking.

Explanation:

Let's say we have a velocity v>0.

The acceleration a is the rate of change of the velocity v. This means that if v is <em>increasing during</em> time, then a must be positive. But if v is <em>decreasing over</em> time, then a will be negative (even though the velocity is positive).

Mathematically:

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2 years ago
The pressure gauge shown below has a spring for which k = 60 N/m, and the area of the piston is 0.50 cm2. Its right end is conne
kicyunya [14]

Answer:

0.025 m

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F=PA\\\Rightarrow F=30000\times 0.5\times 10^{-4}\\\Rightarrow F=1.5\ N

From Hooke's law

F=kx\\\Rightarrow x=\dfrac{F}{k}\\\Rightarrow x=\dfrac{1.5}{60}\\\Rightarrow x=0.025\ m

The spring is compressed 0.025 m

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F_2=101000\times 0.5\times 10^{-4}\\\Rightarrow F_2=5.05\ N

Net force would be

F=F_2-F_1\\\Rightarrow F=5.05-1.5\\\Rightarrow F=3.55\ N

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x=\dfrac{F}{k}\\\Rightarrow x=\dfrac{3.55}{60}\\\Rightarrow x=0.059167\ m

The compression of the spring is 0.059166 m

8 0
3 years ago
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