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Dmitrij [34]
3 years ago
14

In case of frequency of light what changes​

Physics
1 answer:
maks197457 [2]3 years ago
6 0

Answer:

frequency remains constant when light passes through different mediums . only speed changes and due to it , wavelength also changes. one way of changing the frequency is by Doppler effect, where the apparent frequency changes due to motion of the source ,observer or both of them.

Explanation:

hope it helps

good day

Thank u ✌️

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A mass of charged ions that can expand out of an open container would be considered a ______ gas solid plasma liquid
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it may be a gas sorry if it’s wrong

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3 years ago
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An 5-kg animal accelerates from rest to 10 m/s in 10 m and encounters an average drag force of 12 N. What is the average power o
MArishka [77]

Answer:

60 watts

Explanation:

Given that

Mass of the animal, m = 5 kg

Velocity of the animal, v = 10 m/s

Distance moved by the animal, d = 10 m

Drag force, F(d) = 12 N

Time taken, t = 2 seconds

To start with, we need to find the power output in itself before proceeding to find the average power output. And as such, we have

Power = Force * Distance/Time

But Distance/Time is velocity, so

Power = Force * Velocity

Power = 12 * 10

Power = 120 W.

We then use this power gotten to find the average power output.

Power(avg) = P/t

Power(avg) = 120 / 2

Power(avg) = 60 Watts.

Therefore, the average power output is found to be 60 Watts

5 0
4 years ago
2. Two projectiles thrown from the same point at angles 0,=60° and 02=30° with the horizontal,
Liono4ka [1.6K]

Answer:

The answer is below

Explanation:

The maximum height (h) of a projectile with an initial velocity of u, acceleration due to gravity g and at an angle θ with the horizontal is given as:

h=\frac{u^2sin^2\theta}{2g}

Given that the two projectile has the same height.

For\ the\ first\ projectile\ with\ an\ angle\ \60^0 \ with\ the\ horizontal\ and initial\ velocity\ u_1:\\\\h=\frac{u_1^2sin^260}{2g} =\frac{0.75u_1^2}{2g} \\\\For\ the\ second\ projectile\ with\ an\ angle\ \30 \ with\ the\ horizontal\ and initial\ velocity\ u_2:\\\\h=\frac{u_2^2sin^230}{2g} =\frac{0.25u_2^2}{2g}\\\\\frac{0.25u_2^2}{2g}=\frac{0.75u_1^2}{2g}\\\\0.25u_2^2=0.75u_1^2\\\\\frac{u_1^2}{u_2^2} =\frac{0.25}{0.75} \\\\\frac{u_1^2}{u_2^2}=\frac{1}{3} \\\\\frac{u_1}{u_2}=\sqrt\frac{1}{3}

8 0
3 years ago
What are three things that need to be labeled when making a graph?​
Cloud [144]

Answer:

the y axis, the x axis and the title.

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3 years ago
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Mrac [35]

Answer:

C

Explanation:

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