Answer:
The answer is 576.0473
Explanation:
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Answer:
The non-relativistic kinetic energy of a proton is 
The relativistic kinetic energy of a proton is 
Explanation:
Given that,
Mass of proton 
Speed
We need to calculate the kinetic energy for non relativistic
Using formula of kinetic energy

Put the value into the formula


We need to calculate the kinetic energy for relativistic
Using formula of kinetic energy



Hence, The non-relativistic kinetic energy of a proton is 
The relativistic kinetic energy of a proton is 
The magnitude of e.m.f induced in the loop when t = 2 s is 31 Volts.
<h3>emf induced in the loop</h3>
The magnitude of e.m.f induced in the loop is calculated as follows;
emf = dФ/dt
Ф = 6t² + 7t
dФ/dt = 12t + 7
at t = 2 seconds
emf = dФ/dt = 12(2) + 7 = 31 V
Thus, the magnitude of e.m.f induced in the loop when t = 2 s is 31 Volts.
Learn more about emf here: brainly.com/question/24158806
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The Answer is TRUE. Hope it helps