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JulsSmile [24]
3 years ago
8

If ceramic vessels are typed together based as they were all used as storage containers, in spite of the fact that design elemen

ts indicate they are from different time periods, then they have to be
functional typeoperational typesystematic type
Engineering
1 answer:
andriy [413]3 years ago
3 0

If ceramic vessels are typed together based as they were all used as storage containers, in spite of the fact that design elements indicate they are from different time periods, then they have to be  functional typeoperational typesystematic type is given below

Explanation:

The Batiscan site, excavated in the 1960s, produced one of the largest Vinette I collections known to date. Revisiting this ceramic assemblage has revealed more heterogeneity than is generally recognized within the Vinette I type of pottery. Indeed, variations from the typological definition exist, both within and between Early Woodland ceramic collections. A number of diagnostic traits, such as the presence of exterior and interior cord impressions and the absence of decoration, are challenged by the present study. It is hypothesized that part of this variability is chronological, and that the vessels from Batiscan were manufactured closer to the end of the Early Woodland period. However, other factors, such as the frequency and scale of production, and the possible exchange and circulation of ceramic containers, must also be taken into account when interpreting Vinette I variability.l

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When trying to solve a frame problem it will typically be necessary to draw many free body diagrams. a)-True b)-False
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Finally, indeed, it will typically be necessary to draw many-body diagrams. 

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7. Sockets internal designs come in what sizes?
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3 0
3 years ago
-Mn has a cubic structure with a0 = 0.8931 nm and a density of 7.47 g/cm3. -Mn has a different cubic structure, with a0 = 0.63
Fudgin [204]

Answer:

The percentage volume change is -3.0%

Explanation: We are to determine the percentage change that will occurs is alpha-Mn is transformed to beta-Mn

Value are defined as;

Cubic structure (a0) for alpha-Mn = 0.8931nm = 0.8931e-9m = 7.1236e-28cm3

Cubic structure (a0) for beta-Mn = 0.6326nm = 0.6326e-9m = 2.5316e-28cm3

Density of alpha-Mn = 7.47g/cm3

Density of beta-Mn = 7.26g/cm3

Atomic weight of Mn = 54.938g/mol

Atomic radius of Mn = 0.112nm

STEP1: CALCULATE THE ATOM NUMBER PER CELL IN THE ALPHA-Mn;

Atom per cell = (density × cubic structure × Avogadro's constant) ÷ (atomic weight ) × 100000

(7.47× 7.1236e-28 × 6.02e23) ÷ 54.938 = 58.31

Therefore the number of Atom in alpha-Mn is 58.31 atom per cell

STEP2: CALCULATE THE NUMBER OF ATOM PER CELL IN THE BETA-Mn

Atom per cell = (density × cubic structure × Avogadro's constant) ÷ (atomic weight) × 1000000

(7.26 × 2.5316e-28 × 6.02e23) ÷ 54.938 = 20.14

Therefore the number of Atom in beta-Mn is 20.14 atom per cell

STEP3: CALCULATE THE PERCENTAGE VOLUME OF ALPHA-Mn AND BETA-Mn

V% = [(volume of atom × number of atom per cell) ÷ volume of unit cell] × 1000

For Alpha-Mn:

[(1.4049e-30 × 58.31) ÷ 7.1236e-28] × 1000 = 114.998%

For Beta-Mn:

[(1.4049e-30 × 20.14) ÷ 2.5316e-28] × 1000 = 111.766%

STEP4: CALCULATE THE CHANGE IN PERCENTAGE VOLUME FOR ALPHA TO TRANSFORM TO BETA

change = final state - initial state

Therefore;

Change = 111.766 - 114.998 = -3.23%

Therefore for a transformation of Alpha-Mn to Beta-Mn they will be a decrease in volume

3 0
3 years ago
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