I believe its temperature because when something has high temperature it has more thermal energy and when something has low temperature, it has less thermal energy. Hope that helped ^-^

8 0

3 years ago

An object is 2.0 cm from a double convex lens with a focal length of 1.5 cm. Calculate the image distance

Tomtit [17]

Answer:

0.857 cm

Explanation:

We are given that:

The focal length for a convex lens to be (f) = 1.5cm

The object distance (u) = - 2.0 cm

We are to determine the image distance (v) = ??? cm

By applying the lens formula:

$\dfrac{1}{f} = \dfrac{1}{u}+\dfrac{1}{v}$

By rearrangement and making (v) the subject of the above formula:

$v = \dfrac{uf}{u-f}$

replacing the given values:

$v = \dfrac{(-2.0)(1.5)}{(-2.0 -1.5)}$

$v = \dfrac{-3.0}{(-3.5)}$

v = 0.857 cm

3 0

3 years ago

A 7750 kg space probe, moving nose-first toward Jupiter at 179 m/s relative to the Sun, fires its rocket engine, ejecting 72.0 k

Reika [66]

Answer:

179.47m/s

Explanation:

Using the law of conservation of momentum

m1u1 + m2u2 = (m1+m2)v

m1 and m2 are the masses

u1 and u2 are the initial velocities

v is the final velocity

Substitute

7750(179)+72(230) = (7750+72)v

1,387,250+16560 = 7822v

1,403,810 = 7822v

v = 1,403,810/7822

v= 179.47m/s

Hence the final velocity of the probe is 179.47m/s

7 0

3 years ago