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galina1969 [7]
3 years ago
6

17. Alyssa just bought a new set of string lights for her bedroom. She decided to use the lights to outline her mirror. The ligh

ts are on a series circuit. If Alyssa were to buy more lights so that they can go all around her bedroom, what will happen to following quantities?:
a. The resistance of the entire circuit will (increase/decrease).
b. The current through each bulb will (increase/decrease).
c. The voltage available to each bulb will (increase/decrease).
Physics
1 answer:
Ierofanga [76]3 years ago
8 0

a. The resistance will increase

b. The current will decrease

c. The voltage through each bulb will

Explanation:

a. For a series of resistors, the equivalent resistance is given by

R=R_1+R_2+...+R_n

so, we see that adding more resistors in series, will increase the total resistance.

b. In a series circuit, the current through each bulb is the same for each bulb, and it is equal to the current flowing in the circuit, which is given by Ohm's law

I=\frac{V}{R}

where V is the voltage supplied by the battery and R the total resistance of the circuit. Since the voltage provided by the battery, V, does not change, while the total resistance R increases, the current I will increase.

c. The voltage through each bulb is given by

V=R_i I

where R_i is the resistance of the individual resistor and I is the current. Since the value of R_i does not change, while I (the current) has decreased, the voltage available to each bulb, V, will decrease.

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The average speed of a nitrogen molecule in air is about 6.70 ✕ 102 m/s, and its mass is about 4.68 ✕ 10-26 kg.(a) If it takes 3
Sveta_85 [38]

Answer:

a = 4.32*10^15 m/s^2

Explanation:

In order to calculate the acceleration of the nitrogen molecule, you take into account that the force experienced by the molecule, is equal to the change in its momentum:

F=\frac{\Delta p}{\Delta t}=m\frac{\Delta v}{\Delta t}       (1)

m: mass of the nitrogen molecule

Δv: change in the speed of the molecule

Δt: time lapse of the change of the momentum of the molecule = 3.10*10^-13 s

Furthermore, by the Newton second law, you have:

F=ma=m\frac{\Delta v}{\Delta t}\\\\a=\frac{\Delta v}{\Delta t}       (2)

The change in the speed is given by:

\Delta v=v-v_o=6.70*10^2m/s-(-6.70*10^2m/s)=1.34*10^3\frac{m}{s}

where you have taken into account the direction of the initial and final speed.

You replace the values of all parameters in the equation (1) in order to calculate the acceleration:

a=\frac{1.34*10^3m/s}{3.10*10^{-13}s}=4.32*10^{15}\frac{m}{s^2}

The acceleration of the nitrogen molecule is 4.32*10^15m/s^2

5 0
3 years ago
HELP PLS! :/
zlopas [31]

Explanation:

formula: Vi = Vf - (at)

Vi: intial velocity

Vf: final velocity

a: acceleration

t: time

fill in formula with the numbers you are given

Vi= 41.6m - ((9.81 m/s^2)(1.89s))

parenthesis first according to pemdas

Vi= 41.6m - 18.54m/s

Answer: 23.06m/s

disclaimer: I havent done physics in awhile so I have no idea if this is right. just an attempt to help steer you in the right direction hopefully. good luck

7 0
3 years ago
A bicyclist starting from rest applies a force of F 195 N to ride his bicycle across flat ground for a distance of d- 290 m befo
laila [671]

Answer: a) 56,550 J b) 30.1 m/s c) 321 m

Explanation:

a) By definition, work, is the process that does an applied force, in order to produce a displacement in the same direction than the applied force, and can be written as follows;

W = F. d. (scalar product of two vectors)

In this case, as the force is parallel to the displacement, work is directly equal to the product of  the applied force times the displacement (in magnitude), so we can write the following:

W = F. D = 195 N. 290 m = 56,550 J

b) In absence of friction, the work done by the force is equal to the change in the kinetic energy, as it can be showed using the work-energy theorem.

So, in this case, we can put the following:

W = ΔK ⇒F. D = 1/2 mv²

Solving for v, we get:

v=√2.F.D/m = 30.1 m/s

c) Now, if we assume that there is no friction between the bike and the ground, all the kinetic energy must become gravitational potential energy, at some height h.

We can write the following equation

m.g. h = 1/2 mv²

Simplifying, and taking g = 9.8 m/s², we can find h:

h= 46.2 m

Now, we need to know the distance travelled up the incline, which is related with the height h, by the angle that the incline does with the horizontal, as follows:

sin 8.29° = h /d ⇒ d= h / sin 8.29° = 46.2 m / sin 8.29° = 321 m

6 0
4 years ago
An airplane is traveling at a fixed altitude with an outside wind factor. The airplane is headed N 40° W at a speed of 600 miles
bija089 [108]

Answer:\vec{v_R}=\hat{i}[-329.11]+\hat{j}[516.18]

Explanation:

Given

Plane is initially flying with velocity of magnitude v=600\ mph

at angle of 40^{\circ} with North towards west

Velocity of plane airplane can be written as

v_a=600(-\sin 40\hat{i}+\cos 40\hat{j})

Now wind is encountered with speed of v=80\ mph at angle of N45^{\circ}E

v_w=80(\cos 45\hat{i}+\sin 45\hat{j})

resultant velocity

\vec{v_R}=\vec{v_a} +\vec{v_w}

\vec{v_R}=600(-\sin 40\hat{i}+\cos 40\hat{j})+ 80(\cos 45\hat{i}+\sin 45\hat{j})

\vec{v_R}=\hat{i}[-385.67+56.56]+\hat{j}[459.62+56.56]

\vec{v_R}=\hat{i}[-329.11]+\hat{j}[516.18]

for direction \tan \theta =\frac{516.18}{329.11}

\tan \theta =1.568

\theta =57.47^{\circ} west of North

3 0
4 years ago
What is 3.75 x 10^-7?
pogonyaev

Answer:

Explanation:

3.75 * 10^-7

=3.75 * 1/10^7

=3.75/10000000

=3/800000000

any base which has it's power negative do it's reciprocal then the power will be positive.

8 0
3 years ago
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