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allochka39001 [22]

2 years ago

10

A man drops a penny V=0 off the top of the Golden Gate Bridge how fast will the penny be moving when it hits the ground? The gol

den hat bridge is 275 meters tall

1 answer:

BARSIC [14]2 years ago

7 0

Answer:

Vf = 73.4 m/s

Explanation:

This is the case of vertical motion where we have to find the final velocity of the penny when it hits the ground. We can use 3rd equation of motion to find the final velocity:

2gh = Vf² - Vi²

where,

g = 9.8 m/s²

h = height = 275 m

Vf = Final Velocity = ?

Vi = Initial Velocity = 0 m/s

Therefore,

2(9.8 m/s²)(275 m) = Vf² - (0 m/s)²

Vf = √5390 m²/s²

<u>Vf = 73.4 m/s</u>

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PLEASE HELP!!! 25 pts!!

mina [271]

Answer:

The slope of the graph is what you need. That tells you the speed not the velocity. In order to find the velocity you would also need to know the direction of the motion.

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3 years ago

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Distinguish between nonsampling error and sampling error. Choose the correct answer below.

kiruha [24]

Answer:

The correct answer is D.

Non-sampling error is the error that results from under-coverage, non-response bias, response bias, or data-entry errors. Sampling error is the error that results because a sample is being used to estimate information about a population.

Explanation:

Sampling error is related to the variation between the true values of the sample and the population. If occurred, it is always random depending upon the sample chosen.

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5 0

3 years ago

A hockey stick strikes a hockey puck of mass 0.17 kg. If the force exterted on the hockey puck is 35.0 N and there is a force of

GREYUIT [131]

Answer:

$a=190\ m/s^2$

Explanation:

Mass of a hockey puck, m = 0.17 kg

Force exerted by the hockey puck, F' = 35 N

The force of friction, f = 2.7 N

We need to find the acceleration of the hockey puck.

Net force, F=F'-f

F=35-2.7

F=32.3 N

Now, using second law of motion,

F = ma

a is the acceleration of the hockey puck

$a=\dfrac{F}{m}\\\\a=\dfrac{32.3}{0.17}\\\\a=190\ m/s^2$

So, the acceleration of the hockey puck is $190\ m/s^2$ .

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3 years ago

HELP NOWWWWW PLEASE

Finger [1]

Answer:it is A

Explanation:

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7 0

2 years ago

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Water is traveling through a horizontal pipe with a speed of 1.7 m/s and at a pressure of 205 kPa. This pipe is reduced to a new

Arturiano [62]

Answer:

The velocity is $v_2 = 6.8 \ m/s$

The pressure is $P_2 = 204978 Pa$

Explanation:

From the question we are told that

The speed at which water is travelling through is $v = 1.7 \ m/s$

The pressure is $P_1 = 205 k Pa = 205 *10^{3} \ Pa$

The diameter of the new pipe is $d = \frac{D}{2}$

Where D is the diameter of first pipe

According to the principal of continuity we have that

$A_1 v_1 = A_2 v_2$

Now $A_1$ is the area of the first pipe which is mathematically represented as

$A_1 = \pi \frac{D^2}{4}$

and $A_2$ is the area of the second pipe which is mathematically represented as

$A_2 = \pi \frac{d^2}{4}$

Recall $d = \frac{D}{2}$

$A_2 = \pi \frac{[ D^2]}{4 *4}$

$A_2 = \frac{A_1}{4}$

So $A_1 v_1 = \frac{A_1}{4} v_2$

substituting value

$1.7 = \frac{1}{4} * v_2$

$v_2 = 4 * 1.7$

$v_2 = 6.8 \ m/s$

According to Bernoulli's equation we have that

$P_1 + \rho \frac{v_1 ^2}{2} = P_2 + \rho \frac{v_2 ^2}{2}$

substituting values

$205 *10^{3 }+ \frac{1.7 ^2}{2} = P_2 + \frac{6.8 ^2}{2}$

$P_2 = 204978 Pa$

4 0

2 years ago