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Tom [10]
2 years ago
14

What are twin primes between 1 to 100​

Chemistry
1 answer:
Furkat [3]2 years ago
6 0
The twin primes between 1 and 100 are; (3, 5), (5, 7), (11, 13), (17, 19), (29, 31), (41, 43), (59, 61), (71, 73). Hope this helped<3
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Determine the length of the object shown <br>A. 97.8 mm<br>B. 97.80 mm<br>C. 97 mm<br>D. 98 mm​
jeka94

Answer:

A. 97.8 mm  

Explanation:

There are 10 divisions between 9 cm (90 mm) and the end of the ruler (10 cm or 100 mm).

Each division equals 1 mm.

Each 5 mm mark has a longer tick, and the dashed red line is between the 97 mm and 98 mm marks.

You would normally estimate to the nearest tenth of a division. An estimate of 0.8 mm is reasonable.

The length of the object is 97.0 mm + 0.8 mm = 97.8 mm.

B is wrong. You can't possibly estimate to the nearest hundredth of a division.  

C is wrong. The dashed red line slightly before the 98 mm mark.

D is wrong. If the dashed red line were exactly on the 98 mm mark, you would record the measurement as 98.0 mm. This indicates that you measured the object to zero tenths on either side of the mark.

 

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3 years ago
What is the only non metal in group 14
Nostrana [21]
Carbon is the only nonmetal
4 0
3 years ago
A car traveling with constant speed travels 150 km in 7200 s. What is the speed of the car?
Advocard [28]
Speed=distance/time  

D=150km

S=7200s 

Divide the numbers. 

150/7200=0.02km/s <---final answer
5 0
3 years ago
A new grill has a mass of 30.0 kg. you put 1.5 kg of charcoal in the grill. you burn all the charcoal and the grill has a mass o
atroni [7]

The reaction for burning of charcoal or complete combustion is as follows:

C(s)+O_{2}(g)\rightarrow CO_{2}(g)

From the above balanced reaction, 1 mole of carbon releases 1 mole of CO_{2} gas.

Converting mass of charcoal into moles as follows:

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Molar mass of pure carbon is 12 g/mol thus,

n=\frac{1.5\times 10^{3} g}{12 g/mol}=125mol

The same moles of CO_{2} is released. Converting these moles into mass as follows:

m=n×M

Molar mass of CO_{2} is 44 g/mol thus,

m=125mol\times 44 g/mol=5.5\times 10^{3}g

Converting mass into kg,

1g=10^{-3}kg

Thus, total mass of gas released is 5.5 kg.

7 0
3 years ago
*WILL GIVE BRAINLIEST TO CORRECT ANSWER *<br> Question in picture
sineoko [7]
The Answer for this question is : A

1 & 2
5 0
2 years ago
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