Answer:
Required heat Q = 11,978 KJ
Explanation:
Given:
Mass = 5.3 kg
Latent heat of vaporization of water = 2,260 KJ / KG
Find:
Required heat Q
Computation:
Required heat Q = Mass x Latent heat of vaporization of water
Required heat Q = 5.3 x 2260
Required heat Q = 11,978 KJ
Required heat Q = 12,000 KJ (Approx.)
Answer:
5.096*10^-8
Explanation:
Given that
The average value of the electromagnetic wave is 310 mW/m²
To find the maximum value of the magnetic field the wave is closest to, we say
Emax = √Erms
Emax = √[(2 * 0.310 * 3*10^8 * 4π*10^-7)]
Emax = √233.7648
Emax = 15.289
Now, with our value of maximum electromagnetic wave gotten, we divide it by speed of light to get our final answer
15.289 / (3*10^8) = 5.096*10^-8 T
Suffice to say, The maximum value of the magnetic field in the wave is closest to 5.096*10^-8
Use the definition of average acceleration:
<em>a</em> = ∆<em>v</em> / <em>t</em>
If <em>v</em> is the starting speed, then ∆<em>v</em> = 0 - <em>v</em>, so solve for <em>v</em> :
-6.42 m/s² = (0 - <em>v</em>) / (2.85 s)
<em>v</em> = (6.42 m/s²) (2.85 s)
<em>v</em> ≈ 18.3 m/s
Explanation:
Heat is the form of energy that is transferred between systems or objects with different temperatures.....
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