0.118 m is the distance between the two protons.
Mass of proton = 1.6726 × 10⁻²⁷ kg
Weight of proton= 1.6726 × 10⁻²⁷ x 9.81 N
= 1.6408 × 10⁻²⁶ N
Charge of proton = 1.602 × 10⁻²⁹ C
The force between two protons = kq²/r² where, K is a proportionality
constant, q is a charge of proton and
r is the distance between two protons.
= 9 × 10⁹ × (1.602×10⁻¹⁹)²/r²
To calculate distance :
Weight of proton= Force between protons
⇒ 1.6408 × 10⁻²⁶ N = 9 × 10⁹ × (1.602×10⁻¹⁹)²/r²
⇒ r = 0.118m
Therefore, 0.118 m is the distance between the two protons.
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It is an example of "Elastic Potential Energy"
In short, Your Answer would be Option C
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Answer:
1.24 m/s
Explanation:
Metric unit conversion:
9.25 mm = 0.00925 m
5 mm = 0.005 m
The volume rate that flow through the single pipe is

This volume rate should be constant and divided into the 4 narrower pipes, each of them would have a volume rate of

So the flow speed of each of the narrower pipe is:
