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3 years ago

6. What do the key results indicate?

Physics

2 answers:

slega [8]3 years ago

7 0

the key result indicate that how you will achieve the your goal

yuradex [85]3 years ago

3 0

Answer:

The key results explains how you achieve a certain goal. They have to be quantitative, but always measurable in terms of their progress.

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Two 2.00 cm * 2.00 cm plates that form a parallel-plate capacitor are charged to { 0.708 nC. What are the electric field strengt

lisov135 [29]

Answer:

(a) $E=200000Volts/meter$

(b) $E=200000Volts/meter$

Explanation:

Given data

Area A=4.0 cm²=0.0004 m²

Electric permittivity ε=8.854×10⁻¹² farads/meter

Charge q=0.708 nC

To find

(a) Potential at distance=1.00mm

(b) Potential at distance=2.00mm

Solution

For (a) Potential at distance=1.00mm

First we need to find the capacitance

$C=E*A/D\\C=8.854*10^{-12}*(0.0004/1.00*10^{-3} )\\ C=3.5416*10^{-12}farads$

As we know that

$Q=CV\\V=Q/C\\V=(0.708*10^{-9}C )/3.5416*10^{-12}farads\\V=200Volts$

So Electric potential is given as:

$E=V/d\\E=(200V)/(1*10^{-3}m )\\E=200000Volts/meter$

For (b) Potential at distance=2.00mm

First we need to find the capacitance

$C=E*A/D\\C=8.854*10^{-12}*(0.0004/2.00*10^{-3} )\\ C=1.7708*10^{-12}farads$

As we know that

$Q=CV\\V=Q/C\\V=(0.708*10^{-9}C )/1.7708*10^{-12}farads\\V=400Volts$

So Electric potential is given as:

$E=V/d\\E=(400V)/(2.0*10^{-3}m )\\E=200000Volts/meter$

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