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Elan Coil [88]
4 years ago
11

How does a gas do work?

Physics
2 answers:
Triss [41]4 years ago
8 0
Your answer would be C, "By conserving energy"! A gas can do work through something called the First Law of Thermodynamics. Heat that energy used by the gas during this "work" cannot be created or destroyed however it can be transferred and converted. This energy can only be stored during these processes, not removed. An example of this would be gas in a cylindrical object such as a piston. When the gas is heated, it expands and moves the piston upwards. When it expands, it stores that energy it gains through the heat given.

I hope this helps! (:
blsea [12.9K]4 years ago
8 0
C, "By conserving energy"! A gas can do work through something called the First Law of Thermodynamics. Heat that energy used by the gas during this "work" cannot be created or destroyed however it can be transferred and converted. :)
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What gas law looks at the relationship between pressure and temperature of a gas? A) Boyle's Law B) Charles' Law C) Gay Lussac's
Mandarinka [93]

Answer: it should be Boyle’s law

Explanation:

6 0
3 years ago
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Two protons move with uniform circular motion in the presence of uniform magnetic fields. Proton one moves twice as fast as prot
lubasha [3.4K]

Answer:

r₂ = 4 r

Explanation:

For this exercise let's use Newton's second law with the magnetic force

          F = q v x B

bold letters indicate vectors, the magnitude of this expression is

          F = q v B sin θ  

in this case we assume that the angle is 90º between the speed and the magnetic field.

If we use the rule of the right hand with the positive charge, the thumb in the direction of the speed, the fingers extended in the direction of the magnetic field, the palm points in the direction of the force, which is towards the center of the circle, therefore the force is radial and the acceleration is centripetal

           a = v² / r

let's use Newton's second law

           F = ma

           q v B = m v² / r

           r = \frac{qB}{mv}

Let's apply this expression to our case.

Proton 1

             r = \frac{qB_1}{mv_1}

Proton 2

             r₂ = \frac{q \ B_2}{m \  v_2}

in the exercise indicate some relationships between the two protons

*    v₁ = 2 v₂

    v₂ = v₁ / 2

*   B₂ = 2B₁

we substitute

           r₂ = \frac{q \ 2B_1}{m \ \frac{v_1}{2} }

           r₂ = 4 \frac{qB_1}{mv_1}

           r₂ = 4 r

7 0
3 years ago
Determine the speed
Paraphin [41]
Calculating the average speed is simple using the formula <span>speed = distance/time</span>
3 0
4 years ago
What is the efficiency of an engine that exhausts 440 J of heat to a cold reservoir and receives 570 J of heat from a hot reserv
katrin2010 [14]

Answer:

Efficiency = 77%

Explanation:

Input energy = 570 J

Output energy = 440 J

To find the efficiency;

Efficiency = \frac {Out-put \; energy}{In-put \; energy} * 100

Substituting into the equation, we have;

Efficiency = \frac {440}{570} * 100

Efficiency = 0.7719 * 100

Efficiency = 77.19 ≈ 77%

Therefore, the efficiency of the engine is 77 percent.

7 0
3 years ago
We often use a spoon to cool coffee by stirring. Some of the heat is conducted from the coffee to the air by this method, but th
Ilia_Sergeevich [38]

Answer:

Explanation:

heat lost by coffee = heat gain by aluminum spoon

heat lost by coffee = mc ( 85° C - T)

175 ml of water = 175 grams

175 grams = (175 / 1000) kg = 0.175 kg

heat loss by coffee = 0.175 × 4182 J/Kgk ( 85 - T) = 731.85 ( 85-T) = 62207.25 - 731.85 T

heat gain by aluminum spoon = 0.012kg × 897 J/kgK ( T - 22) = 10.764 T - 236.808

10.764 T - 236.808 = 62207.25 - 731.85 T

10.764 T + 731.85 T = 62207.25 + 236.808

T = 84.086 ° C approx 84°C

3 0
3 years ago
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