Answer:
r₂ = 4 r
Explanation:
For this exercise let's use Newton's second law with the magnetic force
F = q v x B
bold letters indicate vectors, the magnitude of this expression is
F = q v B sin θ
in this case we assume that the angle is 90º between the speed and the magnetic field.
If we use the rule of the right hand with the positive charge, the thumb in the direction of the speed, the fingers extended in the direction of the magnetic field, the palm points in the direction of the force, which is towards the center of the circle, therefore the force is radial and the acceleration is centripetal
a = v² / r
let's use Newton's second law
F = ma
q v B = m v² / r
r =
Let's apply this expression to our case.
Proton 1
r = \frac{qB_1}{mv_1}
Proton 2
r₂ = 
in the exercise indicate some relationships between the two protons
* v₁ = 2 v₂
v₂ = v₁ / 2
* B₂ = 2B₁
we substitute
r₂ =
r₂ = 4
r₂ = 4 r
Calculating the average speed is simple using the formula <span>speed = distance/time</span>
Answer:
Efficiency = 77%
Explanation:
Input energy = 570 J
Output energy = 440 J
To find the efficiency;
Substituting into the equation, we have;

Efficiency = 77.19 ≈ 77%
Therefore, the efficiency of the engine is 77 percent.
Answer:
Explanation:
heat lost by coffee = heat gain by aluminum spoon
heat lost by coffee = mc ( 85° C - T)
175 ml of water = 175 grams
175 grams = (175 / 1000) kg = 0.175 kg
heat loss by coffee = 0.175 × 4182 J/Kgk ( 85 - T) = 731.85 ( 85-T) = 62207.25 - 731.85 T
heat gain by aluminum spoon = 0.012kg × 897 J/kgK ( T - 22) = 10.764 T - 236.808
10.764 T - 236.808 = 62207.25 - 731.85 T
10.764 T + 731.85 T = 62207.25 + 236.808
T = 84.086 ° C approx 84°C