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3 years ago

Which of the following is an example of positive potential energy with reference to the floor? PLS HELP

Physics

1 answer:

frutty [35]3 years ago

5 0

Answer:

Explanation:

potential energy is usually at rest at the highest point in comparason to the ground

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the mass of an object is 90 kg calculate weight of the same object on the surface of the moon.(acceleration due to gravity on th

aalyn [17]

Explanation:

the weight of an object is its force exerted by gravity.

on earth we take gravitational acceleration to be 9.8 m/s^2

so the weight of an object on earth is given by F = mg

hence,

F = 90 × 9.8

F = 882 Newtons (weight on earth)

gravitational acceleration on the moon is equal to 9.8/6. so, we can just use the same formula to find the weight on the moon.

F = 90 × 9.8/6

F = 147 Newtons (weight on the moon)

make sure to ask if you need any further guidance.

5 0

2 years ago

Read 2 more answers

A dump truck contains a load of soil. Which action will INCREASE the dump

ANTONII [103]

Answer:

D. Add more soil

Explanation:

8 0

3 years ago

Read 2 more answers

Given that ethylene has a λmax of 175nm, butadiene has a λmax of 220nm, and 2-methyl-1,3-butadiene has a λmax or 215nm, what is

Vika [28.1K]

The λmax of 2,3,4-trimethylhexatriene is 280 nm.

Ethylene has a λmax of 175nm.

Butadiene has a λmax of 220nm.

2-methyl-1,3-butadiene has a λmax or 215nm.

1,3,5-hexatriene has a λmax of 258nm.

Woodward's rules, sometimes known as Woodward-Fieser rules (after Louis Fieser) and named after Robert Burns Woodward, are a number of sets of empirically developed principles that aim to forecast the wavelength of the absorption maximum (max) in an ultraviolet-visible spectrum of a certain molecule.

By using the Woodward Fieser rule,

R- (Alkyl Group) .... +5 nm = 5 × 2 = 10

RO- (Alkoxy Group) .. +6 = 6 × 2 = 12

Adding 22nm to the λmax of 1,3,5-hexatriene as it has 2 alkyl groups and 2 alkoxy groups to form 2,3,4-trimethylhexatriene.

The λmax of 2,3,4-trimethylhexatriene is 280 nm.

Learn more about Woodward-Fieser here:

brainly.com/question/16982345

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5 0

1 year ago

In one of the classic nuclear physics experiments at the beginning of the 20th century, an alpha particle was accelerated toward

Vladimir79 [104]

Answer:

The answer is " $1.01 \times 10^{-13}$ "

Explanation:

Using the law of conservation for energy. Equating the kinetic energy to the potential energy.

$KE=U=\frac{kqq'}{r}\\\\$

Calculating the closest distance:

$\to r=\frac{kqq'}{KE}\\\\$

$=\frac{k(2e)(79e)}{KE}\\\\=\frac{k(2)(79)e^2}{KE}\\\\=\frac{9.0\times 10^9 \ N \cdot \frac{m^2}{c}(2)(79)(1.6 \times10^{-19} \ C)^2}{(2.25\ meV) (\frac{1.6 \times 10^{-13} \ J}{1 \ MeV})}\\\\$

$=\frac{9.0\times 10^9 \times 2\times 79\times 1.6 \times10^{-19}\times 1.6 \times10^{-19} }{(2.25 \times 1.6 \times 10^{-13}) }\\\\=\frac{3,640.32\times 10^{-29}}{3.6 \times 10^{-13} }\\\\=\frac{3,640.32}{3.6} \times 10^{-16}\\\\=1011.2 \times 10^{-16}\\\\=1.01 \times 10^{-13}$

5 0

2 years ago

In 2.8 s, a car increases its velocity from 20. M/s to 25 m/s. What is the acceleration of the car

Akimi4 [234]

Acceleration= change in velocity/time; 5/2.8 , so a=1.785714286

6 0

3 years ago