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3 years ago

How does changing the wavelength alter the frequency of the wave? & How does altering frequency alter pitch?

2 answers:

4 0

For any wave, the product of (wavelength) x (frequency) is always the same number ... it's the speed of the wave. So if you were able to change the wavelength somehow, the frequency would automatically change, in the opposite direction but by the SAME FACTOR, so that their product would stay the same.

If the frequency of a sound changes (and we're close enough to listen to it), our brain interprets that as a change of pitch, in the same direction as the frequency changed.

Rufina [12.5K]3 years ago

3 0

for a given type of wave in a given medium a larger frequency means a smaller wavelength

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Whats the answer? Will give brainliest

kupik [55]

Answer:

The answer to your question is: letter D

Explanation:

Fussion is combine light nuclei to form heavy nuclei

a) This is wrong the definition says, combine light nuclei to form hevier nulcei

b) Both fussion and fission are about radioactive compounds

c) Both fussion and fission use radioactive reactants

d) Yes, this is a characteristic of fussion

6 0

4 years ago

Coulomb's law for the magnitude of the force FFF between two particles with charges QQQ and Q′Q′Q^\prime separated by a distance

SSSSS [86.1K]

Answer:

${F_{tot} = -1.092*10^{-2}N$

Explanation:

The question: What is the net force exerted by these two charges on a third charge q_3 = 47.0 nC placed between q_1 and q_2 at x_3 = -1.240 mm ?

<u>Your answer may be positive or negative, depending on the direction of the force.</u>

Solution:

The coulomb force is given by the equation

$F =k\dfrac{q_1 q_2}{d^2}.$

where $d$ is the separation between the charges $q_1$ and $q_2$ .

Now, in our case

$q_1=-13.5nC=-13.5*10^{-9}C$

$q_2=-1.735nC=-1.735*10^{-9}C$

$q_3= 47*10^{-9}C$

The separation between charges $q_3$ and $q_1$ is

$d_{31}= (-1.240mm)-(-1.735mm)=0.495mm=4.95*10^{-4} m$

Therefore, the force between them is

$F_{31} = (9*10^9NmC^{-2})\dfrac{47*10^{-9}*(-13.5*10^{-9})}{4.95*10^{-4}} =-0.01152N$

and it is directed in the negative x-direction.

The separation between charges $q_2$ and $q_3$ is

$d_{23} =-1.240mm-0=-1.240*10^{-3}m$

therefore, the force between them is

$F_{23} =(9*10^9Nm^2C^{-2})\dfrac{47*10^{-9}C*(-1.735*10^{-9}C)}{-1.240*10^{-3}m}=5.94*10^{-4}N$

Therefore the total force on charge $q_3$ is

$F_{tot} =5.94*10^{-4}-0.01152N = -0.010926N\\\\\boxed{F_{tot} = -1.092*10^{-2}N}$

8 0

3 years ago

A voltage amplifier needs a high input resistance and a low output resistance. Select one: True False

cupoosta [38]

Answer:

Explanation:

In electric circuit , the potential difference is always developed across the resistance .

Now is we are to amplify the voltage , that means low input voltage is converted into high voltage output .

Therefore we require low resistance at input for low voltage and high out put resistance for high output

Thus the statement given is wrong .

6 0

3 years ago

An electric field E⃗ =5.00×105ı^N/C causes the point charge in the figure to hang at an angle. What is θ?

elena-14-01-66 [18.8K]

Explanation:

how difficult question

My head is sppining

4 0

3 years ago

Select the option that best completes the statement: In the absence of a net force, an object can be It is not possible to know

victus00 [196]

In the absence of a net force, an object can be at rest or in motion with a constant velocity.

<h3>What is Newton's first law of motion?</h3>

Newton's first law of motion states that an object at rest or uniform motion in a straight line will continue in that path <u>unless acted upon</u> by an external force.

This law is also called the law of inertia because it depends on mass.

F(net) = ma

when, F(net) = 0, acceleration will be zero and velocity will be constant.

Thus, in the absence of a net force, an object can be at rest or in motion with a constant velocity.

Learn more about net force here: brainly.com/question/11556949

#SPJ1

5 0

2 years ago