Answer:
the energy when it reaches the ground is equal to the energy when the spring is compressed.
Explanation:
For this comparison let's use the conservation of energy theorem.
Starting point. Compressed spring
Em₀ = K_e = ½ k x²
Final point. When the box hits the ground
Em_f = K = ½ m v²
since friction is zero, energy is conserved
Em₀ = Em_f
1 / 2k x² = ½ m v²
v =
x
Therefore, the energy when it reaches the ground is equal to the energy when the spring is compressed.
Answer:
666.6 seconds
Explanation:
if he runs at 3m/sec he will achieve the goal of 2000m in 666.6 seconds. just divide - 3/2000.
note we have changed 2km to 2000metres
Answer:

Explanation:
Given:
- mass of bullet,
- initial velocity of bullet,

- displacement of the bullet in the target,

Here as given in the question the bullet penetrates the target by the given displacement of the bullet into it. During this process it faces deceleration and hence it comes to rest.
- so, final velocity of the bullet,

Now using the equation of motion:

where:
acceleration of the bullet


<u>Now the force of resistance offered by the target in stopping it:</u>



The answer to the question is true
Answer:
D
Explanation: Hope this helps Sorry if it dosent