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2 years ago

8.5 g of rubidium are reacted completely with water.

Chemistry

1 answer:

juin [17]2 years ago

5 0

Answer:

0.040M RbOH

Explanation:

The reaction of Rb with water is:

2Rb + 2H₂O → 2RbOH + H₂

As 2 moles of rubidium produce 2 moles of rubidium hydroxide, we need to find the moles of rubidium added. With these moles and the volume we can find molar concentration of RbOH as follows:

<em>Moles Rb = Moles RbOH -Molar mass Rb = 85.4678g)</em>

8.5g * (1mol / 85.4678g) = 0.099 moles RbOH

As 1dm³ = 1L, the volume in liters is 2.5L

That means molarity is:

0.099 moles RbOH / 2.5L =

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a_sh-v [17]

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Explanation :

The integrated rate law equation for second order reaction follows:

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