Question

What is the magnitude of the electric force between two point charges with Q1 = -1.5 C and Q2 = 0.8 C at a distance of 1 km?

Answer 1

Answer:

F = -10800 N

Explanation:

Given that,

Charge 1, $q_1=-1.5\ C$

Charge 2, $q_2=0.8\ C$

Distance between the charges, $d=1\ km=10^3\ m$

We need to find the electric force acting between two point charges. Mathematically, it is given by :

$F=k\dfrac{q_1q_2}{d^2}$

$F=-9\times 10^9\times \dfrac{1.5\times 0.8}{(10^3)^2}$

F = -10800 N

So, the magnitude of electric force between two point charges is 10800 N. Hence, this is the required solution.