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In-s [12.5K]
3 years ago
10

Why is it that dislocations play an important role in controlling the mechanical properties of metallic materials, however, they

do not play a role in determining the mechanical properties of glasses?
Engineering
1 answer:
klio [65]3 years ago
5 0

Answer:

dislocations play an important role in controlling as

Explanation:

As dislocations plays an important role in the ductility, elasticity and plurality of materials

  • The elastic and elastic deflections play a large role in their properties as the metallic materials, because the dislocation of a glass material does not play a major role in their properties.

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You have 6 resistors in a circuit. The voltage on each is given. Use MATLAB to calculate the total power dissipated by the resis
Semmy [17]
Answer:










Explanation:



0.80 1.7’




I hope this helps! :)
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4 years ago
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Calculate the frequencies (in Hz) for the ten lowest modes of a rigid-wall room of dimensions 2.59m x 2.42m x 2.82m (i.e., find
Digiron [165]

Answer:

For This Answer Please See the Attached File.

Explanation:

Download pdf
3 0
3 years ago
Why metals are good thermal conductors, but polymers are not?
jok3333 [9.3K]

Answer: Metals are good thermal conductors because they have close packaged metal ions in their lattice structure but in polymers they have discontinuous structure which make them poor as a conductor.

Explanation: Metals are considered as good thermal conductors because of their lattice structure which has tightly packed ions in it. In the outer shell of atoms the electrons are free to move and thus conduct the electricity but for the polymers, they have a different structure as compared to metals thus it makes it difficult for a polymer to conduct electricity due to high number of discontinuous particle chains. Therefore metals are good conductors , but polymers are not.

4 0
4 years ago
Consider 4.8 pounds per minute of water vapor at 100 lbf/in2, 500 oF, and a velocity of 100 ft/s entering a nozzle operating at
andriy [413]

Answer:

A) v_2 = 2016.80 ft/s

B) \Delta s = 0.006 Btu/lbm R  

Explanation:

Given data:

P-1 = 100 lbf/in^2

T_1 = 500 degree f

V_1 = 100 ft/s

P_2 = 40 lbf/inc^2

effeciency = 80%

from steady flow enerfy equation

h_1 +\frac{V_1^2}{2} = h_2 + \frac{V_2^2}{2}

where h1 and h2 are inlet and exit enthalpy

for P1 = 100 lbf/in^2 and T1 = 500 degree F

H_1 = 1278.8 Btu/lbm

s_1 = 1.708 Btu/lbm -R

for P1 = 40 lbf/in^2

H_1 = 1193.5 Btu/lbm

s_1 = 1.708 Btu/lbm -R

exit enthalapy h_2

\eta = \frac{h_1 - h'_2}{ h_1 - h_2}

0.80 = \frac{1278.8 - h'_2}{1278.8 -1193.5} = 1197.77 Btu/lbm

from above equation

1278.8 \times 25037 + \frac{100^2}{2} = 1197.77   \times 25037 + \frac{v_2^2}{2}                   [1 Btu/lbm = 25037 ft^2/s^2]

v_2 = 2016.80 ft/s

b) amount of entropy

\Delta s = s_2 - s_1

s_1 = 1.708 Btu/lbm -R

at h_2 = 1197.77 Btu/lbm [\tex]  and [tex]P_2 = 40 lbf/in^2

s_2 is 1.714 Btu/lbm -R

\Delta s = 1.714 - 1.708 = 0.006 Btu/lbm R

6 0
3 years ago
The thermal conductivity of a solid depends upon the solid’s temperature as k = a T+b where a and b are constants. The temperatu
Alexandra [31]

Answer:

Answer is Option (e) - None of these

Explanation:

The step by step derivation from the fourier's law of heat conduction is as shown in the attachment below.

Where K = thermal conductivity

7 0
4 years ago
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