All categories

3 years ago

- Ify=-6 when x= -14, find x when y=-4.

Mathematics

1 answer:

Hitman42 [59]3 years ago

6 0

Answer :

x = - 12 for y = - 4

Step-by-step explanation:

Given as y = - 6 when x = - 14

write in equation form

I.e y = x + c

Put x and y values ,

So, c = y - x

c = - 6 + 14 = 8

Now when y = - 4 and c = 8 ,

So, from eq x = y - c

∴ x = - 4 - 8 = - 12 Answer

You might be interested in

Translate and solve using proportions: What number is 30% of 60

balandron [24]

Answer: 18

Step-by-step explanation:

The question is asked to know 30% of 60, we get

60 x 30% = 60 x 0.3 = 18

3 0

3 years ago

Read 2 more answers

Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used

gladu [14]

Answer:

Part 1) $2x^{2}-32=0----> (-4,4)$

Part 2) $4x^{2}-100=0----> (-5,5)$

Part 3) $x^{2}-55=9----> (-8,8)$

Part 4) $x^{2}-140=-19----> (-11,11)$

Part 5) $2x^{2}-18=0----> (-3,3)$

see the attached figure

Step-by-step explanation:

Solve each quadratic equation

Part 1) we have

$2x^{2}-32=0$

Adds 32 both sides

$2x^{2}=32$

Divide by 2 both sides

$x^{2}=16$

take square root both sides

$x=\pm4$

therefore

The solutions are (-4,4)

Part 2) we have

$4x^{2}-100=0$

Adds 100 both sides

$4x^{2}=100$

Divide by 4 both sides

$x^{2}=25$

take square root both sides

$x=\pm5$

therefore

The solutions are (-5,5)

Part 3) we have

$x^{2}-55=9$

Adds 55 both sides

$x^{2}=9+55$

$x^{2}=64$

take square root both sides

$x=\pm8$

therefore

The solutions are (-8,8)

Part 4) we have

$x^{2}-140=-19$

Adds 140 both sides

$x^{2}=-19+140$

$x^{2}=121$

take square root both sides

$x=\pm11$

therefore

The solutions are (-11,11)

Part 5) we have

$2x^{2}-18=0$

Adds 18 both sides

$2x^{2}=18$

Divide by 2 both sides

$x^{2}=9$

take square root both sides

$x=\pm3$

therefore

The solutions are (-3,3)

7 0

3 years ago

Explain how to create a graph to model the relationship between the 2 quantities in the table. A 2-column table with 4 rows. Col

azamat

Answer:

Sample Response:Use the values in the table to create ordered pairs. Label the x-axis with the independent variable, hours. Label the y-axis with the dependent variable, dollars. Plot the ordered pairs on the graph. If the variables can be represented as fractional parts you can draw a line from the origin that connects the points.

Step-by-step explanation:

I took one for the team D:

4 0

3 years ago

A man weighing 800 N is hanging from a 2 mm diameter titanium wire with a cross-section of 3 x 10^-6 m^2. Will the wire break?

DENIUS [597]

Answer:

Since stress is greater than ultimate strength, the wire will break.

Step-by-step explanation:

The titanium wire is experimenting an axial load. Ultimate strength equals $2.20\times 10^{8}\,Pa$ . The wire shall break if and only if stress is at least equal to ultimate strength. The equation for axial stress ( $\sigma$ ), measured in pascals, in the wire with circular cross-section is:

$\sigma = \frac{4\cdot F}{\pi\cdot D^{2}}$ (1)

Where:

$F$ - Axial force, measured in newtons.

$D$ - Cross-section diameter, measured in meters.

Please notice that axial force is the weight of the man hanging from wire.

If we know that $F = 800\,N$ and $D = 0.002\,m$ , then the axial stress experimented by the titanium wire is:

$\sigma = \frac{4\cdot (800\,N)}{\pi\cdot (0.002\,m)^{2}}$

$\sigma \approx 2.546\times 10^{8}\,Pa$

Since stress is greater than ultimate strength, the wire will break.

3 0

3 years ago

What is a number that is greater than 5 and less than 40, is not divisible by 2, the sum of it's digits is 7 and has exactly 3 f

Doss [256]

Is odd between 5 and 40 is a square number and the digits add to 7.
all the square numbers between there are 9,16, 25, 36
It's not 9, 16 or 36 so it has to be 25

Hope this helps :)

4 0

3 years ago

- Ify=-6 when x= -14, find x when y=-4.​

- Ify=-6 when x= -14, find x when y=-4.