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3 years ago

Which is not a medium through which a mechanical wave could travel?

Physics

2 answers:

Setler [38]3 years ago

8 0

Mechanical Wave cannot travel in space vaccumes, which would be considered "Empty Space" in your situation.

Tems11 [23]3 years ago

8 0

A mechanical cannot travel through empty space. So option (d) is correct.

A mechanical wave is a wave which needs a material medium for its propagation. For example sound, water waves etc . The medium required by the wave can be a solid, liquid or a gas. Empty space doesn't have any medium, so a mechanical wave cannot travel through empty space.

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A solenoid has 332 turns and a length of 14 cm. If a current of 0.88 A produces a magnetic flux density of 0.28 T in the core of

irina1246 [14]

Answer:

106.83

Explanation:

N = 332, l = 14 cm = 0.14 m, i = 0.88 A, B = 0.28 T

Let ur be the relative permeability

B = u0 x ur x n x i

0.28 = 4 x 3.14 x 10^-7 x ur x 332 x 0.88 / 0.14 ( n = N / l)

ur = 106.83

3 0

3 years ago

Two identical circular, wire loops 35.0 cm in diameter each carry a current of 2.80 A in the same direction. These loops are par

defon

Answer:

The answer is " $4659.2 \times 10^{-24} \ N$ "

Explanation:

The magnetic field at ehe mid point of the coils is,

$\to B=\frac{\mu_0 i R^2}{(R^2+x^2)^{\frac{3}{2}}}\\\\$

Here, i is the current through the loop, R is the radius of the loop and x is the distance of the midpoint from the loop.

$\to B=\frac{(4\pi\times 10^{-7})(2.80\ A) (\frac{0.35}{2})^2}{( (\frac{0.35}{2})^2+ (\frac{0.24}{2})^2)^{\frac{3}{2}}}\\\\$

$=\frac{(12.56 \times 10^{-7})(2.80\ A) \times 0.030625}{( 0.030625+ 0.0144)^{\frac{3}{2}}}\\\\=\frac{ 1.07702 \times 10^{-7} }{0.0095538976}\\\\=112.730955 \times 10^{-7}\\\\=1.12\times 10^{-5}\ \ T\\$

Calculating the force experienced through the protons:

$F=qvB=(1.6 \times 10^{-19}) (2600)(1.12 \times 10^{-5})= 4659.2 \times 10^{-24}\ N$

7 0

3 years ago

Two campers dock a canoe. One camper has a mass of 100.0 kg and moves forward at 3.0 m/s as he leaves the canoe to step onto the

Solnce55 [7]

Answer:

The combined speed of camper and canoe is 1.71 m/s.

Explanation:

Given that,

Mass of camper 1, m = 100 kg

Speed of camper 1, v = 3 m/s

The combined mass of another camper and canoe is, M = 175 kg

We need to find the combined speed of camper and canoe. According to the conservation of linear momentum, the momentum of first camper is equal to linear momentum of the canoe and the second camper.

$mv=MV\\\\V=\dfrac{mv}{M}\\\\V=\dfrac{100\times 3}{175}\\\\V=1.71\ m/s$

So, the combined speed of camper and canoe is 1.71 m/s.

4 0

3 years ago

When a dielectric slab is inserted between the plates of one of the two identical capacitors

tatiyna

Answer:(A-P,S;B-P,S;C-Q,S;D-P,S)

Solution

(A)→P,S,(B)→P,S,(C)→Q,S,(D)→P,S.

Explanation:

4 0

2 years ago

Read 2 more answers

Some fish have a density slightly less than that of water and must exert a force (swim) to stay submerged. What force must an 85

vichka [17]

The force require to keep grouper submerged is 8.207N.

According to Archimedes principle buoyant force of any object must equal to weight of fluid it displaced.

The expression for the force exerted to stay submerged in salt water is

F = F(b) - w(fish)

where F(b) = buoyant force

w(fish) = weight

now substitute w(b) for F(b)

→ F = Vρg - w(fish)

where V = volume of sea water

ρ = density of sea water

Now by Archimedes principle V = m(fish) / ρ(fish)

→ F = (m(fish) / ρ (fish) ) ρg - m(fish)g

F = (85 kg/1015 kg-m^-3) (1.025× 10³ kg-m^-3) (9.8 m/s^2)

- (85kg) × 9.8 m/s^2

F = 841.207N - 833N

F = 8.207 N

Hence, the force require to keep grouper submerged is 8.207N.

Learn more about Archimedes Principle here:

brainly.com/question/15076878

#SPJ4

7 0

2 years ago