Perfect Elastic Collisions

Have you ever had a dream that, that, um, that you had, uh, that you had to, you could, you do, you wit, you wa, you could do so

Murljashka [212]

Answer:

I love that video it’s so funny!!!

Explanation:

3 0

3 years ago

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A solenoidal coil with 26 turns of wire is wound tightly around another coil with 350 turns. The inner solenoid is 20.0 cm long

noname [10]

Answer:

Part a)

$\phi = 2.76 \times 10^{-7} T m^2$

Part B)

$M = 5.52 \times 10^{-5} H$

Part C)

$EMF = 0.1 V/s$

Explanation:

Part a)

Magnetic field due to a long ideal solenoid is given by

$B = \mu_0 n i$

n = number of turns per unit length

$n = \frac{N}{L}$

$n = \frac{350}{0.20}$

$n = 1750 turn/m$

now we know that magnetic field due to solenoid is

$B = (4\pi \times 10^{-7})(1750)(0.100)$

$B = 2.2 \times 10^{-4} T$

Now magnetic flux due to this magnetic field is given by

$\phi = B.A$

$\phi = (2.2 \times 10^{-4})(\pi r^2)$

$\phi = (2.2 \times 10^{-4})(\pi(0.02)^2)$

$\phi = 2.76 \times 10^{-7} T m^2$

Part B)

Now for mutual inductance we know that

$\phi_{total} = M i$

$\phi_{total} = N\phi$

$\phi_{total} = 20(2.76 \times 10^{-4})$

$\phi_{total} = 5.52 \times 10^{-6}$

now we have

$M = \frac{5.52 \times 10^{-6}}{0.100}$

$M = 5.52 \times 10^{-5} H$

Part C)

As we know that induced EMF is given as

$EMF = M \frac{di}{dt}$

$EMF = 5.52 \times 10^{-5} (1800)$

$EMF = 0.1 V/s$

3 0

3 years ago

Generally, what will happen to most liquids if the temperature is increased?

GalinKa [24]

Temperature doesn't really affect solubility on liquids so it can only be D besides it's already a liquid....

5 0

3 years ago

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A diode for which the forward voltage drop is 0.7 V at 1.0 mA is operated at 0.5 V. What is the value of the current

Vesnalui [34]

Answer:

the current value is $0.335 \mu A$

Explanation:

The computation of the value of the current is given below:

$z_i = I_s e^{\frac{0.7}{ut} }= 10^{-3}\\\\Z_z = I_s e^{\frac{0.5}{ut} }\\\\\frac{Z_z}{Z_i}= \frac{Z_z}{10^{-3}} = e^{\frac{0.5\times 0.7}{0.025} }\\\\= 0.335 \mu A$

Hence, the current value is $0.335 \mu A$

4 0

3 years ago

A soccer ball with a mass of 0.434 kg approaches a player horizontally with a speed of 13.0 m/s. The player kicks the ball with

zaharov [31]

Answer:

a) 15.49

b) Opposite to the ball's initial velocity

c) 258.16N

Explanation:

a)

$\Delta p=m \Delta v\\\\\Delta p= (0.434)(13.0-(-22.7)) \\\\\Delta p=(0.434)(35.7)\approx 15.49 kg \cdot m/s$

b)

Since the player is kicking the ball in the opposite direction to which it came, the impulse is being directed opposite to the ball's initial velocity.

c)

$\Delta p= F \Delta t \\\\\\F=\dfrac{\Delta p}{\Delta t} \\\\\\F=\dfrac{15.49 kg \cdot m/s}{0.06 s}\approx 258.16N$

Hope this helps!

7 0

3 years ago