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Dmitrij [34]
3 years ago
6

How could you use the barometer to determine the height of a building?

Physics
1 answer:
Nady [450]3 years ago
5 0
Take the barometer to the roof of the building. Drop the barometer from the edge of the roof, and, with your wrist watch or a stop watch, measure the time it takes for the barometer to hit the ground or the street below. Then the height of the roof, in meters, is 4.9 times the square of the time in seconds.
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A charge of 25 nC is uniformly distributed along a straight rod of length 3.0 m that is bent into a circular arc with a radius o
Greeley [361]

Answer:

E = 31.329 N/C.

Explanation:

The differential electric field dE at the center of curvature of the arc is

dE = k\dfrac{dQ}{r^2}cos(\theta ) <em>(we have a cosine because vertical components cancel, leaving only horizontal cosine components of E. )</em>

where r is the radius of curvature.

Now

dQ = \lambda rd\theta,

where \lambda is the charge per unit length, and it has the value

\lambda = \dfrac{25*10^{-9}C}{3.0m} = 8.3*10^{-9}C/m.

Thus, the electric field at the center of the curvature of the arc is:

E = \int_{\theta_1}^{\theta_2} k\dfrac{\lambda rd\theta  }{r^2} cos(\theta)

E = \dfrac{\lambda k}{r} \int_{\theta_1}^{\theta_2}cos(\theta) d\theta.

Now, we find \theta_1 and \theta_2. To do this we ask ourselves what fraction is the arc length  3.0 of the circumference of the circle:

fraction = \dfrac{3.0m}{2\pi (2.3m)}  = 0.2076

and this is  

0.2076*2\pi =1.304 radians.

Therefore,

E = \dfrac{\lambda k}{r} \int_{\theta_1}^{\theta_2} cos(\theta)d\theta= \dfrac{\lambda k}{r} \int_{0}^{1.304}cos(\theta) d\theta.

evaluating the integral, and putting in the numerical values  we get:

E = \dfrac{8.3*10^{-9} *9*10^9}{2.3} *(sin(1.304)-sin(0))\\

\boxed{ E = 31.329N/C.}

4 0
3 years ago
Clarissa thought that learning to play the banjo was a waste of time. She didn't bother to practice after her lessons
emmasim [6.3K]

Answer:

The answer ro this question is fear of failure

7 0
3 years ago
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A student estimated a mass to be 325 g, but the actual mass is 342 g. What is the percent error?
Dovator [93]

Answer:

Answer:

5.2307 %

Explanation:

(acutal mass- estimated mass) / ( estimated mass)

3 0
3 years ago
If I accidentally touch a stove and burn myself, which type of heat transfer is occurring?
allochka39001 [22]

Answer:

radiation is the correct answer

5 0
3 years ago
When 525 J of heat is added to 7.6 g of metal at 26°C, the temperature increases to 80°C. What is the specific heat of the metal
Temka [501]

Ans the answer is 0.25J

Explanation

i guess

4 0
3 years ago
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