Explain why some pesticides bioaccumulate whereas others do not

1 answer:

7 0

Bioaccumulation refers to the accumulation of chemicals in a living organism. The compound or chemical accumulates at a rate faster than it is being metabolized or excreted by the organism. Chemicals bioaccumulate by binding to the proteins and fats in an organism while others bioaccumulate through the repeated consumption of contaminated organisms.

Pesticides containing chemicals that dissolve easily in fat but not in water tend to bioaccumulate. Pesticides that contain chemicals that can easily be metabolized by organisms do not bioaccumulate. In summary, the nature of the chemical used in pesticides and the capability of organisms to metabolize the said chemicals can dictate whether it will bioaccumulate or not.

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A sample of oxygen gas has a volume of 45.8 mL when its pressure is 0.492 atm. What

White raven [17]

Answer:

Explanation:

$P_1=0.492\:atm\\V_1 = 45.8\:ml\\V_2 = ?\\P_1 = 0.954\:atm\\\\Boyle's Law = P_1V_1 = P_2V_2\\\\Lets \:make\: V \:subject\:of\:the\:formula\\\\\frac{P_1V_1}{P_2} = \frac{P_2V_2}{P_2} \\ \\V_2 =\frac{P_1V_1}{P_2} \\V_2 = \frac{0.492\times45.8}{0.954}\\ \\V_2 = \frac{22.5336}{0.954} \\\\V_2 = 23.620\\\\V_2 = 23.6$

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A 500.0 g block of dry ice (solid CO2, molar mass = 44.0 g) vaporizes at room temperature. Calculate the volume of gas produced

Damm [24]

Considering the ideal gas law, the volume of gas produced at 25.0 °C and 1.50 atm is 184.899 L.

<h3>Definition of ideal gas</h3>

An ideal gas is a theoretical gas that is considered to be composed of randomly moving point particles that do not interact with each other. Gases in general are ideal when they are at high temperatures and low pressures.

<h3>Ideal gas law</h3>

An ideal gas is characterized by absolute pressure (P), volume (V), and absolute temperature (T). The relationship between them constitutes the ideal gas law, an equation that relates the three variables if the amount of substance, number of moles n, remains constant and where R is the molar constant of gases:

P×V = n×R×T

<h3>Volume of gas</h3>

In this case, you know:

P= 1.50 atm
V= ?
n= 500 g× $\frac{1 mole}{44 g}$ = 11.36 moles, being 44 $\frac{g}{mole}$ the molar mass of CO₂
R= 0.082 $\frac{atmL}{molK}$
T= 25 C= 298 K (being 0 C=273 K)