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2 years ago

Condensed structural formula of benzoic acid

Chemistry

1 answer:

Deffense [45]2 years ago

5 0

Hmmm I’m not sure just to to quizlet for now but that seems kinda like science and elements

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If there were 10 grams of a radioactive isotope, how much of the sample would be left after 1 half-life? How much after 2 half-l

Vikentia [17]

One half-life: 5 grams
Two half-lives: 2.5 grams

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2 years ago

What can you assume about the anions in the ionic compound copper(II) fluoride? A. The charge on the ionic compound is 2+.

erastova [34]

The answer is C, because if the copper has a +2 charge, the fluoride must have a -2 charge in order to cancel out.

4 0

3 years ago

How many grams of precipitate will be formed when 20.5 mL of 0.800 M

Anton [14]

Answer:

There will be formed 1.84 grams of precipitate (NaNO3)

Explanation:

Step 1: The balanced equation

CO(NO3)2 (aq) + 2 NaOH (aq) → CO(OH)2 (s) + 2 NaNO3 (aq)

Step 2: Data given

Volume of 0.800 M CO(NO3)2 = 20.5 mL = 0.0205 L

Volume of 0.800 M NaOH = 27.0 mL = 0.027 L

Molar mass of NaNO3 = 84.99 g/mol

Step 3: Calculate moles of CO(NO3)2

Moles CO(NO3)2 = Molarity * volume

Moles CO(NO3)2 = 0.800 M * 0.0205

Moles CO(NO3)2 = 0.0164 moles

Step 4: Calculate moles NaOH

moles of NaOH = 0.800 M * 0.027 L

moles NaOH = 0.0216 moles

Step 5: Calculate limiting reactant

For 1 mole CO(NO3)2 consumed, we need 2 moles of NaOH to produce 1 mole of CO(OH)2 and 2 moles of NaNO3

NaOH is the limiting reactant. It will completely be consumed.

CO(NO3)2 is in excess. There willbe 0.0216 / 2 = 0.0108 moles of CO(NO3)2 consumed. There will remain 0.0164 - 0.0108 = 0.0056 moles of CO(OH)2

Step 6: Calculate moles of NaNO3

For 2 moles of NaOH consumed, we have 2 moles of NaNO3

For 0.0216 moles of NaOH, we have 0.0216 moles of NaNO3

Step 7: Calculate mass of NaNO3

mass of NaNO3 = moles of NaNO3 * Molar mass of NaNO3

mass of NaNO3 = 0.0216 moles * 84.99 g/mol = 1.84 grams

There will be formed 1.84 grams of precipitate (NaNO3)

5 0

2 years ago

What is meant by the term sensitivity in Analytical Chemistry? (a) The term refers to the limit at which the absorption instrume

ivolga24 [154]

The term sensitivity in Analytical Chemistry is "the slope of the calibration curve or a function of analyte concentration or amount".

Answer: Option B

Explanation:

In a sample, the little amounts of substances can be accurately evaluated by a method is termed as "Analytical sensitivity". This detect a target analyte like an antibody or antigen, process is considered as potential of a test to and generally demonstrated as the analyte's minimum detectable concentration.

The acceptable diagnostic sensitivity is not guaranteed by high analytical sensitivity. The percentage of individuals who have a given disarray who are identified by the method as positive for the disarray is known as "Diagnostic sensitivity".

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3 years ago

How many grams of barium chloride (BaCl2) are there in 0.187 mol? 0.187 mol

igor_vitrenko [27]

Answer:

38.9 grams of $BaCl_2$