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REY [17]
3 years ago
8

A titration was performed on 50.0mL of 0.250 M NaOH.After the

Chemistry
1 answer:
777dan777 [17]3 years ago
6 0

Answer:

1.750 M

Explanation:

In case of titration , the following formula can be used -

M₁V₁ = M₂V₂

where ,

M₁ = concentration of acid ,

V₁ = volume of acid ,

M₂ = concentration of base,

V₂ = volume of base .

from , the question ,

M₁ = ? M

V₁ = 7.14 mL

M₂ = 0.250 M

V₂ = 50 mL

Using the above formula , the molarity of acid , can be calculated as ,

M₁V₁ = M₂V₂

M₁ * 7.14 mL = 0.250 M * 50mL

M₁ = 1.750 M

Hence, the molarity of the hydrochloric acid = 1.750 M

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