Answer:
No
Explanation:
One mole of P₄ react with six moles of I₂ and gives 4 moles of PI₃.
When one gram phosphorus and 6 gram of iodine react they gives 8.234 g
ram of PI₃ .
Given data:
Mass of phosphorus = 1 g
Mass of iodine = 6 g
Mass of PI₃ = ?
Solution:
Chemical equation:
P₄ + 6I₂ → 4PI₃
Number of moles of P₄:
Number of moles = Mass /molar mass
Number of mole = 1 g / 123.9 g/mol
Number of moles = 0.01 mol
Number of moles of I₂:
Number of moles = Mass /molar mass
Number of moles = 6 g / 253.8 g/mol
Number of moles = 0.024 mol
Now we will compare the moles of PI₃ with I₂ and P₄.
I₂ : PI₃
6 : 4
0.024 :
4/6×0.024 = 0.02
P₄ : PI₃
1 : 4
0.01 : 4 × 0.01 = 0.04 mol
The number of moles of PI₃ produced by I₂ are less it will be limiting reactant.
Mass of PI₃ = moles × molar mass
Mass of PI₃ = 0.02 mol × 411.7 g/mol
Mass of PI₃ = 8.234 g
Answer:
Explanation:
Hello there!
In this case, according to the given information, it turns out possible for us to solve this problem by using the following equation, defined in terms of energy, Planck's constant, wavelength and speed of light:
Thus, we solve for the wavelength as shown below:
And finally plug in the energy, Planck's constant and speed of light to obtain:
Regards!
Answer:
i cant read it but its c and a
Explanation:
my thinking faces
Answer:
Explanation:
<u>1) Data:</u>
a) V₁ = 38.2 liter
b) P₁ = 91 psi
c) V₂ = 77.4 liter
d) P₂ = ?
<u>2) Formula:</u>
According to Boyle's law, at constant temperature, the pressure and volume of a fixed amount of gas are inversely related:
- PV = constant ⇒P₁V₁ = P₂V₂
<u>3) Solution:</u>
- Solve for the unknown: P₂ = P₁V₁ /v₂
- Substitute the values: V₂ = 91 psi × 38.2 liter / 77.4 liter = 44.9 9si ≈ 45 psi.
