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3 years ago

15

What is the theory of punctuated equilibrium answers?

2 answers:

belka [17]3 years ago

5 0

Answer:

The theory of punctuated equilibrium is a theory of evolutionary biology that aims to explain the pattern of speciation, which is observed in the fossil records. It states that the organism is in the stasis, until a major changes cause evolutionary pressure, which leads to a rapid speciation until stability is again reached between the organism.

Example: A species of sea animals live, breed and dies from thousands of years, suddenly the sea level changes and animals adapt to that situation.

kherson [118]3 years ago

3 0

The theory of punctuated equilibrium states that is a species appear in a fossil record, they will become stable over time and can show little changes in evolution as time goes by. An example would be the feline creatures. Although cats and tigers have a different structure in their body, the facial structure and the way they hunt are similar.

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The Mars Curiosity rover was required to land on the surface of Mars with a velocity of 1 m/s. Given the mass of the landing veh

Aliun [14]

Answer:

The value is $A = 39315 \ m^2$

Explanation:

From the question we are told that

The velocity which the rover is suppose to land with is $v = 1 \ m/s$

The mass of the rover and the parachute is $m = 2270 \ kg$

The drag coefficient is $C__{D}} = 0.5$

The atmospheric density of Earth is $\rho = 1.2 \ kg/m^3$

The acceleration due to gravity in Mars is $g_m = 3.689 \ m/s^2$

Generally the Mars atmosphere density is mathematically represented as

$\rho_m = 0.71 * \rho$

=> $\rho_m = 0.71 * 1.2$

=> $\rho_m = 0.852 \ kg/m^3$

Generally the drag force on the rover and the parachute is mathematically represented as

$F__{D}} = m * g_{m}$

=> $F__{D}} = 2270 * 3.689$

=> $F__{D}} = 8374 \ N$

Gnerally this drag force is mathematically represented as

$F__{D}} = C__{D}} * A * \frac{\rho_m * v^2 }{2}$

Here A is the frontal area

So

$A = \frac{2 * F__D }{ C__D} * \rho_m * v^2 }$

=> $A = \frac{2 * 8374 }{ 0.5 * 0.852 * 1 ^2 }$

=> $A = 39315 \ m^2$

8 0

3 years ago

A 0.750kg block is attached to a spring with spring constant 13.5N/m . While the block is sitting at rest, a student hits it wit

vazorg [7]

Answer:

A)A=0.075 m

B)v= 0.21 m/s

Explanation:

Given that

m = 0.75 kg

K= 13.5 N

The natural frequency of the block given as

$\omega =\sqrt{\dfrac{K}{m}}$

The maximum speed v given as

$v=\omega A$

A=Amplitude

$v=\sqrt{\dfrac{K}{m}}\times A$

$0.32=\sqrt{\dfrac{13.5}{0.75}}\times A$

A=0.075 m

A= 0.75 cm

The speed at distance x

$v=\omega \sqrt{A^2-x^2}$

$v=\sqrt{\dfrac{K}{m}}\times \sqrt{A^2-x^2}$

$v=\sqrt{\dfrac{13.5}{0.75}}\times \sqrt{0.075^2-(0.075\times 0.75)^2}$

v= 0.21 m/s

5 0

2 years ago

According to newtons third law, the two forces in a force pair act

aliina [53]

B- Same force

It’s b because force always acts in equal but opposite pairs.

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2 years ago

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Ierofanga [76]

Are there any options??

I would have to say metal of course but without options I can't assume anything

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3 years ago

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natita [175]

The tropical rain forest is located mostly on Islands. Mainly found in Africa.

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2 years ago

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