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4 years ago

What is the theory of punctuated equilibrium answers?

Physics

2 answers:

belka [17]4 years ago

5 0

Answer:

The theory of punctuated equilibrium is a theory of evolutionary biology that aims to explain the pattern of speciation, which is observed in the fossil records. It states that the organism is in the stasis, until a major changes cause evolutionary pressure, which leads to a rapid speciation until stability is again reached between the organism.

Example: A species of sea animals live, breed and dies from thousands of years, suddenly the sea level changes and animals adapt to that situation.

kherson [118]4 years ago

3 0

The theory of punctuated equilibrium states that is a species appear in a fossil record, they will become stable over time and can show little changes in evolution as time goes by. An example would be the feline creatures. Although cats and tigers have a different structure in their body, the facial structure and the way they hunt are similar.

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An open pipe, 0.29 m long, vibrates in the second overtone with a frequency of 1,227 Hz. In this situation, the fundamental freq

Andru [333]

Answer:

f = 409 Hz

Explanation:

We have,

Length of the open organ pipe, l = 0.29 m

Frequency of vibration of second overtone, $f_2 = 1227 Hz$

It is required to find the fundamental frequency of the pipe. For the open organ pipe, the frequency of second overtone is given by :

$f_2=\dfrac{3v}{2l}$

v is speed of sound

Let f is the fundamental frequency. It is given by :

$f=\dfrac{v}{2l}$

The relation between f and f₂ can be written as :

$f_2=3f\\\\f=\dfrac{f_2}{3}\\\\f=\dfrac{1227}{3}\\\\f=409\ Hz$

So, the fundamental frequency of the pipe is 409 Hz.

6 0

3 years ago

It is desired to construct a solenoid that will have a resistance of 4.10 Ω (at 20°C) and produce a magnetic field of 4.00 ✕ 10^

Nikolay [14]

Answer:

Part a)

$N = 754 turns$

Part b)

$L = 0.376 m$

Explanation:

Resistance of the solenoid is given as

R = 4.10 ohm

now we have

$R = \rho \frac{L}{A}$

here we know that

$\rho = 1.7 \times 10^{-8} ohm-m$

$A = \pi r^2 = \pi (\frac{0.5 \times 10^{-3}}{2})^2$

$A = 1.96 \times 10^{-7} m^2$

now from above formula

$4.10 = (1.7 \times 10^{-8})\frac{L}{1.96 \times 10^{-7}}$

$L = 47.35 m$

Part a)

now we know that it is wounded over the solenoid

so here we can say

$N(2\pi R) = L$

$N(2 \pi (0.01)) = 47.35$

$N = 754 turns$

Part b)

now length of solenoid is given as

$L = N(diameter\: of\: the\: wire)$

$L = 754(0.5 \times 10^{-3})$

$L = 0.376 m$

6 0

3 years ago

Read 2 more answers

For a projectile with no air resistance, at the peak of its path, _______________.

3241004551 [841]

Answer: "For a projectile with no air resistance, at the peak of its path, it's velocity is equal to zero"

Explanation:

Suppose that you throw an object up. The initial vertical velocity will be positive, and the acceleration (the gravitational acceleration) will point downwards, meaning that it opposes to the initial direction of the velocity, and that decreases the velocity as the time goes by.

There will be a point where the velocity ( that was positive until now, so until now the height of the object was increasing), is equal to zero, this means that at this moment the object stops moving, and after, because we still have negative acceleration, the velocity will start become negative, and the object will fall down.

Then that point where the velocity was zero is the peak of its path, then we can conclude that:

"For a projectile with no air resistance, at the peak of its path, it's velocity is equal to zero"

4 0

3 years ago

In a jump spike, a volleyball player slams the ball from overhead and toward the opposite floor.

USPshnik [31]

V ( initial ) = 20 m/s
h = 2.30 m
h = v y * t + g t ² / 2
d = v x * t
1 ) At α = 18°:
v y = 20 * sin 18° = 6.18 m/s
v x = 20 * cos 18° = 19.02 m/ s
2.30 = 6.18 t + 4.9 t²
4.9 t² + 6.18 t - 2.30 = 0
After solving the quadratic equation ( a = 4.9, b = 6.18, c = - 2.3 ):
t 1/2 = (- 6.18 +/- √( 6.18² - 4 * 4.9 * (-2.3)) ) / ( 2 * 4.9 )
t = 0.3 s
d 1 = 19.02 m/s * 0.3 s = 5.706 m
2 ) At α = 8°:
v y = 20* sin 8° = 2.78 m/s
v x = 20* cos 8° = 19.81 m/s
2.3 = 2.78 t + 4.9 t²
4.9 t² + 2.78 t - 2.3 = 0
t = 0.46 s
d 2 = 19.81 * 0.46 = 9.113 m
The distance is:
d 2 - d 1 = 9.113 m - 5.706 m = 3.407 m

7 0

3 years ago

Marissaâs car accelerates uniformly at a rate of +2.60 m/sÂ². How long does it take for Marissaâs car to accelerate from a speed

DIA [1.3K]

Answer:

The time taken by the car to accelerate from a speed of 24.6 m/s to a speed of 26.8 m/s is 0.84 seconds.

Explanation:

Given that,

Acceleration of the car, $a=+2.6\ m/s^2$

Initial speed of the car, u = 24.6 m/s

Final speed of the car, v = 26.8 m/s

We need to find the time taken by the car to accelerate from a speed of 24.6 m/s to a speed of 26.8 m/s. The acceleration of an object is given by :

$t=\dfrac{v-u}{a}$

$t=\dfrac{(26.8-24.6)\ m/s}{2.6\ s}$

t = 0.84 seconds

So, the time taken by the car to accelerate from a speed of 24.6 m/s to a speed of 26.8 m/s is 0.84 seconds. Hence, this is the required solution.

4 0

4 years ago