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jarptica [38.1K]
3 years ago
14

What mass of water must be used to make a 1.35 m solution that contains 8.20 mol NaOH?

Chemistry
1 answer:
Sergeeva-Olga [200]3 years ago
6 0
Answer is: <span>mass of water is 6.07 kilograms.
</span>b(NaOH) = 1.35 m.
n(NaOH) = 8.20 mol.
b(NaOH) = n(NaOH) ÷ m(H₂O).
m(H₂O) = n(NaOH) ÷ b(NaOH).
m(H₂O) = 8.20 mol ÷ 1.35 mol/lg.
mm(H₂O) = 6.07 kg.
m - molality.
n - amount of substance.
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<h3>What is density?</h3>

A material's density is defined as its mass per unit volume.

Given data:

The density of ethanol = 0.7890 g/mL

The density of water = 0.9982 g/mL

The density of mixture = 0.926 g/mL

Let the % composition of ethanol = x

Let the % composition of water = 100-x

Now density of the mixture

\frac{Mass}{Volume}

Mass = \frac{percent  \;of  \;ethanol  \;X  \;density  \;of  \;ethanol  \;+  \\ \;percent  \;of  \;water X  \;density  \;of  \;water}{100}

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x= 34.51 %

Hence,

% composition of ethanol = 34.51%

% composition of water = 65.49%

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