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ollegr [7]
3 years ago
12

two toy cars can roll without friction on a horizontal surface. Car A is a 5 kg. Car B is 0.5 kg. Both cars start from rest. Equ

al sized forces are used to push each cart forward for a time of 1 second. After 1 second the force is removed. What is the difference in magnitude of the momenta of the two cars, right after the force is removed?Choices:A. The momentum of car A(5kg) is EQUAL to that of car B(0.5)B. The momentum of car A (5kg) is LESS than that car B (0.5)C. The momentum of car A (5kg) is MORE than that car B (0.5)D. 5.5 kg m/s
Physics
1 answer:
Llana [10]3 years ago
8 0

Answer:

A. The momentum of car A(5kg) is EQUAL to that of car B(0.5)

Explanation:

The moment, or impulse formula of the same forces acting on both car within 1 second is

\Delta p = F * \Delta t

In our case the forces are the same, the time duration of force acting on the cars are the same. Therefore, their momentum right after the force must also be the same.

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An atom with more or less neutrons than expected is a what ?
salantis [7]

Answer:

Isotope it will have a different number of neutrons than normal

4 0
2 years ago
Lúc 7g bạn an đi từ nhà đến trường với tóc độ trung bình là 20km/h . Bạn đến trường lúc 7g20. Tính khoảng cách từ nhà tới trường
Len [333]

Answer:

Distance = 6.667 kilometres

Explanation:

Given the following data;

Speed = 20 km/h

Departure time = 7:00

Arrival time = 7:20

Time taken = 20 minutes

To calculate the distance travelled from home to school;

First of all, we would have to convert the value of time in minutes to hours.

Conversion:

60 minutes = 1 hour

20 minutes = X hours

Cross-multiplying, we have;

X = 20/60 = 1/3 hours

Mathematically, the distance travelled by an object is calculated by using the formula;

Distance = speed * time

Distance = 20 * 1/3

Distance = 20/3 =

Distance = 6.667 kilometres

7 0
2 years ago
Suppose an object’s initial velocity is 10 m/s and its final velocity is 4 m/s. Mass is constant.
Ostrovityanka [42]

The correct answer is:

Work is negative, the environment did work on the object, and the energy of the system decreases.

In fact, the work-energy theorem states that the work done by the system is equal to its variation of kinetic energy:

W=\Delta K=K_f -K_i

In this problem, the variation of kinetic energy \Delta K is negative (because the final velocity is less than the initial velocity), so the work is negative, and this means that the environment did work on the object, and its energy decreased.

3 0
3 years ago
Read 2 more answers
Can some one help me with this question its hard :( down below ill give brainliest
tensa zangetsu [6.8K]
I’m pretty sure it’s c sorry if I’m wrong
3 0
3 years ago
Which of the following is not a characteristic of electromagnetic light waves?
SOVA2 [1]

Answer:

they cant travel through a vacuum

7 0
2 years ago
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