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astra-53 [7]
2 years ago
11

A Imagine you derive the following expression by analyzing the physics of a particular system: v2 + 2az. The problem requires so

lving for z , and the known values for the system are a 2.55 meter/second, to = 21.8 meter/second, and u = 0 meter/second. Perform the next step in the analysis
Physics
1 answer:
Nuetrik [128]2 years ago
7 0

Answer:

  z = 93.2 m

Explanation:

We can appreciate that this expression is equivalent to the linear motion equation with constant acceleration

           v² = v₀² + 2 a d

If we make a term-to-term comparison with the expression obtained, they are equivalent

          u² = v² + 2 a z

From here we can clear the position

           2 a z = u² –v²

           z = (u² –v²) / 2 a

Let's calculate

For the speed to reduce the acceleration must be negative

         

         z = (0 - 21.8²) / 2(- 2.55)

         z = 93.2 m

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Suppose that the Hubble Space Telescope discovers a series of planets with the following characteristics moving around a star th
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Answer:

Option (D)

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2 years ago
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gtnhenbr [62]
The first rule of vectors is that the horizontal and vertical components are separate. Disregarding air resistance, the only thing we have to worry about is gravity.

The appropriate suvat to use for the vertical component is v = u +at
I will take a to be -9.81, you may have to change it to be 10 if your qualification likes g to be 10.

v = 30 + (-9.81x2)
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Therefore we know that after 2.0 s the vertical component will be 10.38ms^-1, ie 10m/s as the answers given are all to 2sf.

The horizontal component is completely separate to the vertical component and since there is no air resistance, it will remain constant throughout the projectiles trajectory. Therefore it will remain at 40ms^-1.

Combining this together we get:
(1) vx=40m/s and vy=10m/s

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