Answer:
The smallest distance the student that the student could be possibly be from the starting point is 6.5 meters.
Explanation:
For 2 quantities A and B represented as
and 
The sum is represented as
For the the values given to us the sum is calculated as

Now the since the uncertainity inthe sum is 
The closest possible distance at which the student can be is obtained by taking the negative sign in the uncertainity
Thus closest distance equals
meters
Answer:
0.002372187708 kg
Explanation:
Each atom of Uranium 235 releases 200 MeV = 200×10⁶×1.60218×10⁻¹⁹
= 200×1.60218×10⁻¹³ Joule
Number of atoms in a 2.6 kg sample mass = (2.6/0.235)×6.02214076×10²³
⇒Number of atoms in a 2.6 kg sample mass = 66.627×10²³ atoms
Change in energy = Change in mass / (speed of light)²
ΔE = Δmc²
⇒200×1.60218×10⁻¹³×66.627×10²³ = Δm×(3×10⁸)²
⇒Δm = 200×1.60218×10⁻¹³×66.627×10²³/(3×10⁸)²
⇒Δm = 2372.187708×10⁻⁶ kg
∴Change in mass = 0.002372187708 kg
Answer:
300 N
Explanation:
force = mass × acceleration
= 60 kg × 5m/s^2
= 300 N