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melamori03 [73]
4 years ago
12

Tamiko it's creating a list of characteristics traditionally associated with males in American society. which current characteri

stic should she include in the list?
A. Is competative
B. Likes the color pink
C. Likes to cook
D. Is graceful
Physics
2 answers:
docker41 [41]4 years ago
7 0

Answer:

A. Is competative  

Explanation:

Most American men have a very strong concept of masculinity and different from the rest of the world. In the Americas, men often believe that to show their masculinity, men need to be strong, competitive, brute and sporty, and skilled. In the Americas there is a habit of stating that men may not like pink because it is a girl color and removes its masculinity, just as many men say they do not like to cook because they believe this is an exclusive activity of women. , also believe that grace makes them feminine. So if Tamiko is creating a list of traits traditionally associated with American men, she may include that American men are generally competitive.

Irina-Kira [14]4 years ago
3 0
It is A !! Woot woot
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I understand that electric field can exist without any magnetic field, although it is also generated by varying magnetic field, but as much I know, magnetic fields don't exist independently, they are generated by varying electric field or moving charge. Even in any magnetic substance, magnetic field is generated due to electrons orbiting the nucleus, and electrons have their own electric field, so electric field is present there as well.
7 0
3 years ago
Water flows through a water hose at a rate of Q1 = 860 cm3/s, the diameter of the hose is d1 = 1.85 cm. A nozzle is attached to
Snowcat [4.5K]

Answer:

a) A1 =  \frac{\pi (d1)^{2} }{4}

b) A1 = 2.688 cm^{2}

c) Q1 = A1 x v1

d) v1 = 3.1994 m/s

e) A2 = \frac{A1 X v1}{v2}

f)  A2 = 0.7963cm^{2}

Explanation:

a) Area = \pi r^{2}

r = \frac{d}{2}

thus,

area = \pi (\frac{d}{2})^{2}

A1 =  \frac{\pi (d1)^{2} }{4}[/tex]b) d1 = 1.85 cmsubstituting in the above equation,A1 =  [tex]\frac{\pi (d1)^{2} }{4}

A1 =  \frac{\pi (1.85)^{2} }{4}

A1 = 2.688 cm^{2}

c) Flow rate = Area x velocity ( refer brainly.com/question/13997998)

Q1 = A1 x v1

d) From the above equation,

v1 = \frac{Q1}{A1} = \frac{860}{2.688} = 319.94 cm/s = 3.1994 m/s

e) Since the flow rate Q1 is constant throughout the hose, Av is a constant.

i.e. A1 x v1 = A2 x v2

thus,

A2 = \frac{A1 X v1}{v2}

f) v2 = 10.8 m/s.

substituting the values in the above equation,

A2 = \frac{2.688 X 3.1994}{10.8}  = 0.7963cm^{2}

3 0
4 years ago
An iron anchor of density 7890.00 kg/m3 appears 299 N lighter in water than in air. (a) What is the volume of the anchor? (b) Ho
PtichkaEL [24]

Answer:

weigh is 2353.13 N

Explanation:

Given data

density = 7890.00 kg/m3

lighter =  299 N

to find out

the volume of the anchor and weigh in air

solution

from question we can say that

apparent weight = actual weight - buoyant force

we know weight = mg and buoyant force = water density × g

so volume of anchor is = actual weight - apparent weight / buoyant force

volume of anchor is = 299 / 1000 × 9.81

volume of anchor is = 0.0304791 m³

and

weight of anchor is mg

here mass m = density Fe g

density Fe = 7870 from table 14-1

so weight = 7870 × 0.0304791  × 9.81

weigh is 2353.13 N

7 0
4 years ago
Is electricity a compound, element, or a mixture?
sveta [45]
Electricity is a compound
3 0
4 years ago
In Space, an astronaut releases a wrench from his hand. The wrench has a mass of 4 grams and is traveling with a velocity of -15
Vladimir [108]

Answer:

v_2=8.85\times 10^{-4}\ m/s

Explanation:

We have,

Mass of a wrench, m₁ = 4 g = 0.004 kg

Speed of wrench, v₁ = -15 m/s

Mass of the Astronaut, m₂ = 70 kg

It is required to find Astronaut's velocity. Let it is v₂. Using the conservation of linear momentum to find it.

m_1v_1=m_2v_2\\\\v_2=\dfrac{m_1v_1}{m_2}\\\\=\dfrac{0.004\times (-15)}{70}\\\\=-8.85\times 10^{-4}\ m/s

So, his velocity is 8.85\times 10^{-4}\ m/s.

8 0
3 years ago
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