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melamori03 [73]
4 years ago
12

Tamiko it's creating a list of characteristics traditionally associated with males in American society. which current characteri

stic should she include in the list?
A. Is competative
B. Likes the color pink
C. Likes to cook
D. Is graceful
Physics
2 answers:
docker41 [41]4 years ago
7 0

Answer:

A. Is competative  

Explanation:

Most American men have a very strong concept of masculinity and different from the rest of the world. In the Americas, men often believe that to show their masculinity, men need to be strong, competitive, brute and sporty, and skilled. In the Americas there is a habit of stating that men may not like pink because it is a girl color and removes its masculinity, just as many men say they do not like to cook because they believe this is an exclusive activity of women. , also believe that grace makes them feminine. So if Tamiko is creating a list of traits traditionally associated with American men, she may include that American men are generally competitive.

Irina-Kira [14]4 years ago
3 0
It is A !! Woot woot
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Why can light travel through outer space, but sound cannot?
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Usually, sound needs a medium to travel through, like a vacuum for example. 

Light does not need a medium to travel, and since air is considered a medium, light is not dependent on that. 

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The hydrogen and helium under the clouds of Jupiter are in liquid form due to _____.
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Very short pulses of high-intensity laser beams are used to repair detached portions of the retina of the eye. The brief pulses
Tom [10]

Answer:

a) U = 0.375 mJ

b) p_rad = 4.08 mPa

c) λ_med = 604 nm  ; f_med = 3.7 * 10^14 Hz

d) E_o  = 3.04 * 10^4 V / m , B _o = 1.013 *10^-4 Nm/Amp  

Explanation:

Given:

λ_air : wavelength = 810 * 10^(-9) m

P: Power delivered  = 0.25 W

d : Diameter of circular spot = 0.00051 m

c : speed of light vacuum = 3 * 10^8 m/s

n_air : refraction Index of light in air = 1

n_med : refraction Index of light in medium = 1.34

ε_o : permittivity of free space = 8.85 * 10^-12 C / Vm

part a

The Energy delivered to retina per pulse given that laser pulses are 1.50 ms long:

U = P*t

U = (0.25 ) * (0.0015 )

U = 0.375 mJ

Answer : U = 0.375 mJ

part b

What average pressure would the pulse of the laser beam exert at normal incidence on a surface in air if the beam is fully absorbed?

                   

                                                p_rad = I / c

Where I : Intensity = P / A

                                                p_rad = P / A*c        

Where A : Area of circular spot = pi*d^2 / 4

                                               

                                                 p_rad = 4P / pi*d^2*c  

                              p_rad = 4(0.25) / pi*0.00051^2*(3.0 * 10^8)      

                                                 p_rad = 0.00408 Pa                          

Answer : p_rad = 4.08 mPa

part c

What are the wavelength and frequency of the laser light inside the vitreous humor of the eye?

                                    λ_med =  n_air*λ_air / n_med

                                     λ_med = (1) * (810 nm) / 1.34

                                           λ_med = 604 nm

                                               f_med = f_air

                                          f_med = c /  λ_air

                                 f_med = (3*10^8) / (810 * 10^-9)

                                          f_med = 3.7 * 10^14 Hz

Answer : λ_med = 604 nm  ; f_med = 3.7 * 10^14 Hz

d)

What is the electric and magnetic field amplitude in the laser beam?

                                        I = P / A

                                I  = 0.5*ε_o*c*E_o ^2

                                   I = 4P / pi*d^2

Hence,              E_o = ( 8 P /  ε_o*c*pi*d^2 ) ^ 0.5

E_o = ( 8 * 0.25 / (8.85*10^-12) * (3*10^8) * π * (0.00051)^2) ^ 0.5

                                 E_o  = 3.04 * 10^4 V / m

For maximum magnetic field strength:

                                      B_o = E_o / c

                         B_o = 3.04 * 10^4 / (3*10^8)

                         B _o = 1.013 *10^-4 Nm/Amp      

Answer: E_o  = 3.04 * 10^4 V / m , B _o = 1.013 *10^-4 Nm/Amp      

5 0
3 years ago
A point charge of -4.28 pC is fixed on the y-axis, 2.79 mm from the origin. What is the electric field produced by this charge a
makkiz [27]

Answer:

E = (-3.61^i+1.02^j) N/C

magnitude E = 3.75N/C

Explanation:

In order to calculate the electric field at the point P, you use the following formula, which takes into account the components of the electric field vector:

\vec{E}=-k\frac{q}{r^2}cos\theta\ \hat{i}+k\frac{q}{r^2}sin\theta\ \hat{j}\\\\\vec{E}=k\frac{q^2}{r}[-cos\theta\ \hat{i}+sin\theta\ \hat{j}]              (1)

Where the minus sign means that the electric field point to the charge.

k: Coulomb's constant = 8.98*10^9Nm^2/C^2

q = -4.28 pC = -4.28*10^-12C

r: distance to the charge from the point P

The point P is at the point (0,9.83mm)

θ: angle between the electric field vector and the x-axis

The angle is calculated as follow:

\theta=tan^{-1}(\frac{2.79mm}{9.83mm})=74.15\°

The distance r is:

r=\sqrt{(2.79mm)^2+(9.83mm)^2}=10.21mm=10.21*10^{-3}m

You replace the values of all parameters in the equation (1):

\vec{E}=(8.98*10^9Nm^2/C^2)\frac{4.28*10^{-12}C}{(10.21*10^{-3}m)}[-cos(15.84\°)\hat{i}+sin(15.84\°)\hat{j}]\\\\\vec{E}=(-3.61\hat{i}+1.02\hat{j})\frac{N}{C}\\\\|\vec{E}|=\sqrt{(3.61)^2+(1.02)^2}\frac{N}{C}=3.75\frac{N}{C}

The electric field is E = (-3.61^i+1.02^j) N/C with a a magnitude of 3.75N/C

8 0
3 years ago
A bolt is to be tightened with a torque of 7.0 N · m. If you have a wrench that is 0.55 m long, what is the least amount of forc
kodGreya [7K]

To solve this problem we will apply the given concept for torque which explains the relationship between the force applied and the distance to a given point. Mathematically this relationship is given as

\tau = F*d \rightarrow F = \frac{\tau}{d}

Where,

\tau = Torque

F = Force

d = Distance

Our values are given as,

\tau = 7.0Nm , d = 0.55m

Therefore replacing we have that the force is

F = \frac{7}{0.55}

F = 12.72N

Therefore the least amount of force that you must exert is 12.72N

4 0
3 years ago
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