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Mariulka [41]
3 years ago
11

The seventh grade class is putting on a variety show to raise money. It cost $700 to rent the banquet hall that they are going t

o use. If they charge $15 for each ticket, how many tickets do they need to sell in order to raise at least $1,000
Mathematics
2 answers:
Rainbow [258]3 years ago
6 0
67 tickets so they can sell $1000 at least.
Doss [256]3 years ago
4 0
They will need to raise at least 67 tickets because if they sold 66 tickets (15x66) they will only get $990, but if they get 67 tickets (15x67) they'll raise $1005.  The easiest way to get the answer fast is to do 1,000 divided by 15 and then see if that number equals 1000, or if you need to add one more ticket to make it at least 1,000. 
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If you're factoring, your answer is

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You'll work it out this way:

16x^2 + 8x - 15

Since there's no GCF here, you multiply the first and third terms, giving you -240. Your next step is to find two numbers that have a sum of 8 and a product of -240. These numbers are 20 and -12. Plug those in and you've got:

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From here you divide it into two binomials. These are (16x^2 + 20x) and (-12x - 15).
When you take out the greatest common factors (4x and -3), they become:

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Then you group what's outside of the parentheses together (4x - 3)
And bring what's inside of the parentheses down (4x + 5).
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