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SVETLANKA909090 [29]
3 years ago
12

What happens to the muscle of dmd while working out

Chemistry
1 answer:
oee [108]3 years ago
6 0
DMD is characterized by a total or near total (<3%), absence of the cell membrane protein dystrophin. The absence of dystrophin results in a steady degradation of muscle fibers that causes progressive loss of muscle strength and functional abilities.
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What volume of water has the same mass as 9.0m3 of ethyl alcohol?
Triss [41]
This question requires the knowledge of density. 

The density of ethyl alcohol = 789 kg m⁻³
The density of water = 1000 kg m⁻³

Density = Mass / Volume 

By applying ethyl alcohol,
    789 kg m⁻³ = Mass / 0.9 m³
         Mass     = 710.1 kg
hence the mass of 0.9 m³ ethyl alcohol is 710.1 kg.

Then by applying water,
     1000 kg m⁻³ = 710.1 kg / Volume
      Volume        = 0.7101 m³
                          = 0.7 m³
hence the equal water volume is 0.7 m³
8 0
3 years ago
Which of these is a carbohydrate?<br> O C6H1206<br> O C6H6012<br> C6H1302N<br> C3H7O2NS
amm1812

Answer: The answer is the second choice.

Explanation:

4 0
3 years ago
Read 2 more answers
Scientists use models to
telo118 [61]
B- Predict the damages due to an earthquake
4 0
2 years ago
Using the balanced equation given below, calculate the number of moles of CaBr2 produced in the reaction of 5.0 moles of AlBr3.
allochka39001 [22]

Answer:

7.5 moles of CaBr2 are produced

Explanation:

Based on the equation:

2AlBr3 + 3CaO → Al2O3 + 3CaBr2

<em>2 moles of AlBr3 produce 3 moles of CaBr2 if CaO is in excess.</em>

<em />

Using this ratio: 2 moles AlBr3 / 3 moles CaBr2. 5 moles of AlBr3 produce:

5 moles AlBr3 * (3 moles CaBr2 / 2 moles AlBr3) =

<h3>7.5 moles of CaBr2 are produced</h3>

<em />

4 0
2 years ago
ViT2 = V2T, V = V2
shusha [124]

Answer:

V₂ = 285 mL

Explanation:

Given data:

Initial volume of bag = 250 mL

Initial temperature = 19.0°C

Final temperature = 60.0°C

Final volume = ?

Solution:

The given problem will be solved by using Charles Law,

This law stated that " The volume of given amount of gas at constant pressure and constant number of moles is directly proportional to its temperature"

Mathematical relationship:

V₁/T₁  = V₂/T₂

Now we will convert the temperature into kelvin.

Initial temperature = 19.0 + 273 = 292K

Final temperature = 60.0 + 273 = 333K

Now we will put the values in formula:

V₁/T₁  = V₂/T₂

250 mL / 292K  =  V₂/ 333K

0.856 mL /K = V₂/ 333K

V₂ = 0.86×333K. mL /K

V₂ = 285 mL

7 0
3 years ago
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