Answer:
Final speed of security car v = 65 m/s
Explanation:
Given:
Speed of race car u1 = 35m/s
Speed of security car u2 = 5 m/s
Acceleration = 5 m/s²
Find:
Final speed of security car v
Computation:
Assume, they chase S meter
So
S = u1t + [1/2]at²
S = 35t
S = u2t + [1/2]at²
so,
35t = 5t + [1/2](5)t²
t = 12 s
So
v = u + at
v = 5 + 5(12)
Final speed of security car v = 65 m/s
Given:
mass = 6 kg
velocity = 4 m/s
To find:
Kinetic energy of the cart = ?
Formula used:
Kinetic energy = 
Where m = mass of the cart
v = velocity with which the cart is moving
Solution:
Kinetic energy of the moving cart is given by,
Kinetic energy =
Where m = mass of the cart
v = velocity with which the cart is moving
Kinetic energy =
Kinetic energy = 48 Joule
Thus, the kinetic energy of the moving cart is 48 Joule.
Answer:
Explanation:
I am sitting on a train car traveling horizontally at a constant speed of 50 m/s. I throw a ball straight up into the air. Before , the ball gets separated from my hand , both me the ball will be moving with velocity of 50 m /s in horizontal direction .
As soon as ball is separated from the hand , it acquires addition velocity in upward direction and acceleration in downward direction . This will give relative velocity to the ball with respect to me . So I will see the ball going in upward direction under gravitational acceleration . It appears as if I am sitting at rest and ball is going in upward direction under deceleration . My motion at 50 m/s will have no effect on the motion of ball in upward direction , according to first law of Newton . It is so because ball too will be moving in forward direction with the same speed which will not be visible to me because I too am moving with the same speed.
If I am sitting at rest at home and I threw a ball straight up into the air , I will have the same experience of seeing ball going in similar way as described above.
The energy required to start a reaction IS called the activation energy. TRUE
