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Ghella [55]
3 years ago
6

The light intensity incident on a metallic surface with a work function of 1.88 eV produces photoelectrons with a maximum kineti

c energy of 1.2 eV.
if the frequency of the light is doubled, what is the maximum kinetic energy of the photoelectrons?
Answer in units of eV.

​
Physics
1 answer:
ivanzaharov [21]3 years ago
7 0

Answer:

KE = KE (incidental) - KE of emitted photons

or KE = h * f - Wf

So   h * f = KE + Wf = 1.2 + 1.88 = 3.08    incident energy

If you double the frequency then h * f = 6.16

KE = 6.16 - 1.2 = 4.96 eV

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-- His <em>displacement </em>when he arrives at his front door is

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D = (100m + 70m)East + (30m)West

D = (170m East) + (30m West)

<em>D = 140 meters East </em>

It's interesting to notice that his displacement is 60 meters shorter than the distance he walked.  

That's because there's a stretch of 30 meters somewhere in the middle that he actually covered <em>three times</em>.

Two of those times added to the distance his shoes covered (2x30m=60m), but they cancelled out of the displacement.

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Which category of energy originates in the process of photosynthesis?
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Solar energy ....................
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Two sites are being considered for wind power generation. In the first site, the wind blows steadily at 7 m/s for 3000 hours per
slavikrds [6]

Answer:

E.year₂ > E.year₁  (Second site is better)

Explanation:

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V_{1}=7 m/s\\Time_{1}=3000 hours/year\\V_{2}=10m/s\\Time_{2}=1500hours/year

The  power generation is the time rate of kinetic energy which can be calculated as:

Power=ΔKE=m×V²/2

Regarding  that m ∝ V.Then

Power ∝ V³ ⇒ Power=constant×V³

Since ρa is constant for both sides and Area is the same as same wind turbine is used

For First site

Power_{1}=const.V^3\\Power_{1}=const.(7m/s)^3\\Power_{1}=const.343Watt\\

For second site

Power_{2}=const.V_{2}^3\\Power_{2}=const.(10m/s)^3\\Power_{2}=const.1000W

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E.year=Power×Operation time per year

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E.year₂=Power₂×Operation time₂ per year

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So

E.year₂ > E.year₁  (Second site is better)

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Answer:

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