Answer:
0.167 kJ
Explanation:
Given:
Volume of oil delivered by the pump (V) = 0.628 dm³ = 628 cm³ [1 dm³ = 1000 cm³]
Density of the oil (d) = 0.776 g/cm³
Acceleration due to gravity (g) = 9.8 m/s²
Time for which pump runs (t) = 41 s
Height to which oil is raised (h) = 35 m
Now, we know that, mass of a body is equal to the product of its volume and density. Therefore,
mass of oil (m) = volume × density
Now, work done by the pump is equal to the increase in the potential energy of the oil being raised to the given height.
Increase in potential energy is given as:
Therefore, the work done by the pump is given as:
Work done = ΔU
Now, 1 J = 0.001 kJ
Therefore, 167.04 J = 167.04 × 0.001 = 0.167 kJ
Hence, work done by the pump in kilojoules is 0.167 kJ