Answer:
Explanation:0.493 M NaOH means 0.493 mol NaOH/L
mols
mols = ------ x L
L
mols = M x V
In a titration procedure, 40.57 mL of 0.493 M NaOH solution was used. How many mols NaOH did this volume of NaOH solution contain?
mols = M x V
0.493 mols NaOH
mols = ----------------------- x 0.04057 L
L
mols = 0.0200 mols NaOH
<h3>1. Br₂ decreased : system moving to the left</h3><h3>2. HBr increased : system moving to the left</h3><h3>Further explanation</h3>
In the equilibrium system, according to Le Chatelier, if there is a reaction there will be action
<h3>Reaction = - action</h3>
If the concentration of one component is enlarged, the system reaction is to reduce the component, and vice versa, if the concentration of one component is reduced, the reaction system is to add to the component
From reaction :
H₂(g) + Br₂(g) ⇔ 2HBr(g)
- After the concentration of Br₂ is decreased :
The system will react by increasing the concentration of reagents by moving to the left
- After the concentration of HBr is increased.
The system will react by decreasing the concentration of product by moving to the left
Learn more
Kc for reaction
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Keywords : equilibrium, the concentration,reactant or product,HBR,Br₂
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In an ideal case, the acid would completely protonate. such an acid would be a strong acid. Dissociation of Formic acid looks like:
HCOOH + H₂O → COOH⁻ + H₃O⁺
one mole of formic acid should give one mole of Hydronium(H₃O⁺) ions
similarly, 0.1 moles of formic acid should produce 0.1 moles of hydronium ions. but we know that it is not the case, a much lesser amount is actually formed.
Which means that Formic acid did not completely dissociate into COOH⁻ and H⁺ ions.
Hence, Formic Acid is a weak acid
Answer: 0.2885J/g°c
Explanation:
Loss of heat of metal = Gain of heat by the water
Therefore
-Qm = +Qw
Where
Q = mΔTCp
Q = heat
M= mass
ΔT = T.f - Ti
Ti= initial temperature
T.f= final temperature
Cp= Specific heat (m is metal, w is water)
-Qm = +Qw
-[m(T.f-Ti)Cpm] = m(T.f-Ti)Cpw
Therefore
-[83.2g(28.42-90.31)Cpm] = 41.82g(28.42-
19.93)4.194J/g°c
Cpm = 1485.54÷ 5149.25
Cpm = 0.2885J/g°c
Therefore , the specific heat of the metal is 0.2885J/g°c
