Answer:
The thickness of the oil slick is 
Explanation:
Given that,
Index of refraction = 1.28
Wave length = 500 nm
Order m = 1
We need to calculate the thickness of oil slick
Using formula of thickness

Where, n = Index of refraction
t = thickness
= wavelength
Put the value into the formula



Hence, The thickness of the oil slick is 
The force is opposite to the displacement
Answer:
c.100 minutes
Explanation:
Total distance = 10 km
Runs for 1 km every 5 minutes
walks 1 km every 15 min
She alternates between walking and running so, Jessica will walk 5 km and run 5 Km
Time taken by Jessica for walking
: 5 km
Time taken to walk 1 km=5 minutes
Time taken to walk 5 km
=> 5 X 5
=>25 minutes
Time taken by Jessica for Running
: 5km
Time taken to run 1 km = 15 minutes
=> 5 X 15
=>75 minutes
Total time taken = Time taken by Jessica for walking + Time taken by Jessica for Running
=>25 minutes +75 minutes
=> 100 minutes
Using the equation E = hc/λ we can find out how much energy a single photon of wavelength 193 nm has. E = Planck Constant * Speed of Light/193 nm
Answer:
A 75.1 N and a direction of 152° to the vertical.
B 85.0 N at 0° to the vertical.
Explanation:
A) The interaction partner of this normal force has what magnitude and direction?
The interaction partner of this normal force is the component of the weight of the crate perpendicular to the ramp. <u>It has a magnitude of 85cos28° = 75.1 N and a direction of 180° - 28° = 152° to the vertical(since it is directed downwards perpendicular to the ramp).</u>
B) The normal and frictional forces are perpendicular components of the contact force exerted on the crate by the ramp. What is the magnitude and direction of the contact force?
Since this force has to balance the weight of the crate, its magnitude is 85.0 N. Its direction has to be vertically opposite to that of the weight.
Since the weight is 180° to the vertical (since it is directed downwards), this force is 0° to the vertical.
<u>So, this force has a magnitude of 85.0 N and a direction of 0° to the vertical.</u>