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4 years ago

10

A sled is pushed with 30 Newtons and sliding friction is 10 Newtons find the net force on the sled

1 answer:

mixas84 [53]4 years ago

5 0

The net force is basically the speed or we could call it the centre of gravity. So it's simple:

to find the centre you minus the 2 numbers -

30 - 10 = 20

so the net force is 20

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Here

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$\omega =$ Angular velocity

Here we have that,

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4 years ago

A student of mass 60.0 kg, starting at rest, slides down a slide 20.0 m long, tilted at an angle of 30.0° with respect to the ho

cricket20 [7]

Answer:

Explanation:

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R = mgcos30

=60 x 9.8 x .866

= 509 N

Force of kinetic friction

= .12 x 509

= 61.08 N

b )

net force downwards = mgsinθ - μmgcosθ

acceleration = g sinθ - μgcosθ

9.8 sin30 - .12 x 9.8 x cos30

= 4.9 - 1.018

a= 3.88 m /s²

c )

v² = 2as

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3 years ago

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Eddi Din [679]

Answer:

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