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solong [7]
3 years ago
11

What type of reaction is   3Ca(OH)2 + Al2(SO4)3 = 3CaSO4 + 2Al(OH)3 Combustion, Synthesis, Decomposition, Single Displacement, D

ouble Displacement, or Acid-Base Neutralization
Chemistry
1 answer:
Alexeev081 [22]3 years ago
3 0
Answer is: <span>Double Displacement.
Combustion is reaction with oxygen.
</span>Synthesis is reaction of two or more substances combining to make a more complex substance. 
Decomposition is reaction where one substance is broken down into two or more simpler substances. 
Single Displacement is reaction where  neutral element metal or nonmetal become an ion as it replaces another ion in a compound. 
<span>Double displacement reactions (more reactive metals displace metals with lower reactivity).
</span>Neutralization<span>is is </span>reaction<span> in which an </span>acid<span> and a </span>base<span> react quantitatively with each other.</span>

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The reason people describe water as a universal solvent is because it dissolves almost anything.
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Which of the following planets has ammonia clouds in its atmosphere?
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Jupiter and Saturn has ammonia clouds in its atmosphere since the molecules of ammonia gas that are present in their atmospheres condense to form clouds. However, these ammonia clouds are more visible in Jupiter than in Saturn because of their lower altitude in Saturn.

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All of the covalent carbon-carbon bonds in unsaturated hydrocarbons share 2 pairs of electrons.
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3 years ago
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At 850°C, CaCO3 undergoes substantial decomposition to yield CaO and CO2. Assuming that the ΔH o f values of the reactant and pr
Xelga [282]

Answer:

The enthalpy if 68.10 grams of CO2 is produced is  -189.04 kJ

Explanation:

<u>Step 1:</u> Data given

temperature = 850 °C

Mass of 68.10 grams of CO2

ΔH°f (CaO) = -635.6 kJ/mol

ΔH°f (CO2) = -693.5 kJ/mol

ΔH°f (CaCO3) =-1206.9 kJ/mol

<u>Step 2: </u>The balanced equation

CaCO3(s) → CaO(s) + CO2(g)

<u>Step 3:  </u>Calculate ΔH°reaction

ΔH°reaction = ΣΔH°f (products) - ΣΔH°f (reactants)

ΔH°reaction = (ΔH°f (CaO) + ΔH°f (CO2)) -  ΔH°f (CaCO3)

ΔH°reaction = (-635.6 kJ/mol + -693.5 kJ/mol) + 1206.9 kJ/mol

ΔH°reaction = -122.2 kJ /mol

<u>Step 4:</u> Calculate moles of CO2

Moles CO2 = mass CO2 / Molar mass CO2

Moles CO2 = 68.10 grams / 44.01 g/mol

Moles CO2 = 1.547 moles

<u>Step 5:</u> Calculate the enthalpy change for 68.10 grams of CO2

-122.2 kJ/mol * 1.547 moles = -189.04 kJ

The enthalpy if 68.10 grams of CO2 is produced is  -189.04 kJ

7 0
3 years ago
Current of 250. a flows for 24.0 hours at an anode where the reaction occurring is as follows: mn2+(aq) + 2h2o(l) → mno2(s) + 4h
Tju [1.3M]
From Faraday's 1st law of electrolysis,
Total electricity passed into system = Q = IT = 250 X 24 X 60 X 60
                                                                       = 2.16 X 10^7 C

We know that, 96500 C = 1 F
∴ 2.16 X 10^7 C =  <span>223.8 F
</span>
Now, number of moles of<span> MnO2  deposited = 223.8/2=111.9 
</span>
Finally, 1 mole of MnO2 ≡ 86.94 g
∴ 111.9 mole of MnO2 ≡  111.9 X 86.94 = 9728 g

Thus, <span>mass of MnO2 that will be deposited at anode = 9728 g</span>
7 0
3 years ago
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