C9H20 + 14O2 --> 9CO2 + 10H2O
Answer: 43.3 l
Explanation:
1) Chemical equation:
2 Li(s) + 2 H₂O (l) → 2LiOH(aq) + H₂ (g)
2) Mole ratios:
2 mol Li : 2 mol H₂O : 2 mol LiOH : 1 mol H₂
3) Number of moles of Li that react
n = mass in grams / atomic mass = 24.6g / 6.941 g/mol = 3.54 moles
4) Yield
Proportion:
2 mol Li / 1 mol H₂ = 3.54 mol Li/ x
⇒ x = 3.54 mol Li × 1 mol H / 2 mol Li = 1.77 mol H₂
4) Ideal gas equation
PV = nRT ⇒ V = nRT / P
V = 1.77 mol × 0.0821 [atm×l / (mol×K)] × 301 K / 1.01 atm = 43.3 l
V = 43.3 l ← answer
The formula for Kw is:
Kw= [H]*[OH]
where [H] and [OH] are
concentrations
We are given the pH so we can calculate the [H]
concentration from the formula:
pH=-log[H]
7.43 = -log[H]
[H] = 3.715x10^-8 M
In neutral solution, [H] = [OH], therefore:
<span>[OH]= 3.715x10^-8 M
Calculating Kw:
Kw = (3.715x10^-8)*( 3.715x10^-8)</span>
<span>Kw = 1.38 x 10^-15 </span>
Answer:
B) Lose electrons to form positive ions
Explanation:
