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2 years ago

Explain ways that organisms interact in helpful and harmful ways.

1 answer:

4 0

Organisms are living things. Us humans are also living things, so we are helpful and harmful to other organisms. For example: we can help another human being with something, or we can help a plant/tree grow if we water it. In return, they also help us by providing us with oxygen. however, we can also be harmful to each other and the environment, for example: we can't hurt each other, or plant or animals by killing them or we can hurt insects by stepping on them. Therefore, organisms are helpful and harmful to each other.

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Which acide will have more strength out of two acids of pH value 2 and 5 why

gladu [14]

Ph 2 will ahve more strength due to the fact that its more acidic compared to pH 5.

the lower the number of a pH, the more it is heading towards being acidic, but the higher the number, the more it heads towards being an alkali. here is a ppt i made along time ago. hope it can help you . have a nice day

Download pptx

5 0

2 years ago

An atom that undergoes radioactive decay and has a large nucleus most likely contains..

mojhsa [17]

An atom that undergoes radioactive decay and has a large nucleus most likely contains....- More protons than electrons.

5 0

2 years ago

Key terms: Reset Stereoisomers that are not mirror images of each are ____________ . The chemical and physical properties of two

sergejj [24]

Answer:

Enantiomers/ Isomers/ Stereoisomers/ Meso compounds/ Constitutional isomers/ Diastereomers.

Explanation:

Isomers are molecules that have the same chemical formula but have different conformation, or in its connections, or the orientation in space. Isomers have different chemical and physical properties (second blank).

The isomers that only differ by the orientation of their atoms in space are called stereoisomers (third blank).

The stereoisomers that have a chiral carbon and do not mirror images of each are called enantiomers (first blank). They can deviate the polarized light.

When a compound has two or more chiral carbons but they compensate for the deviation of the light, and the compound is optically inactive, it's called a meso compound (fourth blank).

When the isomers differ in the way the atoms are connected it's called a constitutional isomer (fifth blank).

When the molecule has more than one chiral carbon, it will have pairs of enantiomers. The isomers that aren't of the same pair are nonsuperimposable mirror images of each other and are called diastereomers (last blank).

6 0

2 years ago

PLEASE HELP WITH HIS DUE SOON WILL GIVE BRAINLIST HELP!!

Readme [11.4K]

Answer:

320

Explanation:

8*8*5

8 0

2 years ago

Based on the sign of E cell, classify these reactions as spontaneous or non spontaneous as written.? assume standard conditions.

sammy [17]

A electrochemical reaction is said to be spontaneous, if $E^{0} cell is positive.$

Answer 1:
Consider reaction: Ni^2+ (aq) + S^2- (aq) ----> + Ni (s) + S (s)

The cell representation of above reaction is given by;
 $S^{2-}/S // Ni^{2+}/Ni$

Hence, $E^{0}cell = E^{0} Ni^{2+/Ni} - E^{0} S/S^{2-}$
we know that, ${E^{0} Ni^{2+}/Ni = -0.25 v$
and ${E^{0} S/ S^{2-} = -0.47 v$

Therefore, $E^{0} cell$ = - 0.25 - (-0.47) = 0.22 v

Since, $E^{0} cell$ is positive, hence cell reaction is spontaneous
.....................................................................................................................

Answer 2:
Consider reaction: Pb^2+ (aq) +H2 (g) ----> Pb (s) +2H^+ (aq)

The cell representation of above reaction is given by;
 $H_{2} / H^{+} // Pb^{2+} /Pb$

Hence, $E^{0}cell = E^{0} Pb/Pb^{2+} - E^{0} H_{2}/H^{+}$
we know that, ${E^{0} Pb^{2+}/Pb = -0.126 v$
and ${E^{0} H_{2}/ H^{+} = -0 v$

Therefore, $E^{0} cell$ = - 0.126 - 0 = -0.126 v

Since, $E^{0} cell$ is negative, hence cell reaction is non-spontaneous.

....................................................................................................................

Answer 3:
Consider reaction: 2Ag^+ (aq) + Cr(s) ---> 2 Ag (s) +Cr^2+ (aq)

The cell representation of above reaction is given by;
 $Cr/Cr^{2+} // Ag^{+}/Ag$

Hence, $E^{0}cell = E^{0} Ag^{+}/Ag - E^{0} Cr/Cr^{2+}$
we know that, ${E^{0} Ag^{+}/Ag = -0.22 v$
and ${E^{0} Cr/ Cr^{2+} = -0.913 v$

Therefore, $E^{0} cell$ = - 0.22 - (-0.913) = 0.693 v

Since, $E^{0} cell$ is positive, hence cell reaction is spontaneous

8 0

3 years ago

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