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3 years ago

What charges are needed in the objects to attract both objects?

Physics

2 answers:

kvasek [131]3 years ago

8 0

Answer:

both

Explanation:

Verizon [17]3 years ago

4 0

Answer:

a neutral object will atract the both object

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A current of 3.6-A flows through a conductor. Calculate how much charge passed through and cross-section of the conductor in 25s

Anastaziya [24]

Answer:

90 C

Explanation:

Electric current: This can be defined as the rate of flow of electric charge in a circuit. This can be expressed mathematically as,

I = dQ/dt

dQ = Idt

∫dQ = ∫Idt

Q = It................................ Equation 1

Where Q = amount of charge, I = current, t = time.

Given: I = 3.6 A, t = 25 s.

Substituting into equation 1,

Q = 3.6(25)

Q = 90 C.

Hence the amount of charge passing through the cross section of the conductor = 90 C

6 0

3 years ago

The term solstice translates as "Sun stop." Explain why this translation makes sense from an astronomical point of view. It make

adoni [48]

Answer:

It makes sense because on that the day the sun stops moving northward and starts moving southward

Explanation:

4 0

3 years ago

Read 2 more answers

A car starts from rest and after 20 seconds it's velocity becomes 108km find the acceleration of the car

andre [41]

Answer:

1.5 km/s²

Explanation:

Given that:

a car starts from rest; it means the initial velocity (u) = 0 km/hr = 0 m/s

after time (t) = 20 seconds

the final velocity = 108 km/hr = 30 m/s

The acceleration (a) of the car can be determined by using the formula:

$a = \dfrac{v-u}{t}$

$a = \dfrac{30\ m/s -0 \ m/s}{20 \ s}$

$a = \dfrac{30 \ m/s}{20 \ s}$

a = 1.5 km/s²

7 0

3 years ago

An observer on Earth sees rocket 1 leave Earth and travel toward Planet X at 0.3c. The observer on Earth also sees that Planet X

Verizon [17]

Answer:

0.625 c

Explanation:

Relative speed of a body may be defined as the speed of one body with respect to some other or the speed of one body in comparison to the speed of second body.

In the context,

The relative speed of body 2 with respect to body 1 can be expressed as :

$u'=\frac{u-v}{1-\frac{uv}{c^2}}$

Speed of rocket 1 with respect to rocket 2 :

$u' = \frac{0.4 c- (-0.3 c)}{1-\frac{(0.4 c)(-0.3 c)}{c^2}}$

$u' = \frac{0.7 c}{1.12}$

$u'=0.625 c$

Therefore, the speed of rocket 1 according to an observer on rocket 2 is 0.625 c

5 0

3 years ago

The speed of a car is 40m/s after 10 sec suddenly there was a crowd and the driver reduces its speed to 20m/s. What is the decel

aliya0001 [1]

Explanation:

the number 0.4 in P4 from east

4 0

2 years ago