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goldenfox [79]
3 years ago
15

A major component of gasoline is octane C8H18. When liquid octane is burned in air it reacts with oxygen O2 gas to produce carbo

n dioxide gas and water vapor. Calculate the moles of carbon dioxide produced by the reaction of 0.085mol of oxygen. Be sure your answer has a unit symbol, if necessary, and round it to 2 significant digits.
Chemistry
1 answer:
Nady [450]3 years ago
7 0

Answer:

0.054 moles of carbon dioxide will be produced

Explanation:

Step 1: Data given

Number of moles oxygen = 0.085 moles

Step 2: The balanced equation

2C8H18 + 25O2 → 16CO2 + 18H2O

Step 3: Calculate moles of carbon dioxide

For 2 moles octane we need 25 moles oxygen gas to produce 16 moles carbon dioxide gas and 18 moles water vapor

0.0544

For 0.085 moles O2 we'll have 16/25 * 0.085 = 0.054 moles CO2

0.054 moles of carbon dioxide will be produced

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Why are 1-chlorobutane and 2-chlorobutane structural isomers?.
Nutka1998 [239]

Answer: they both have the same molecular formula but different structural formulae

Explanation:

hope this helps :)

6 0
2 years ago
Which is the correct order largest to smallest
expeople1 [14]

Answer:

how am i suppose to put it in largest to smallest if u didnt give any numbers

6 0
3 years ago
A diploid somatic ("body") cell has 2n = 20 chromosomes. At the end of mitosis, each daughter cell would have ______ chromosomes
kozerog [31]

Answer:

At the end of mitosis, 2n = 20

At the end of meiosis I, n = 10

At the end of meiosis II, n = 10

Explanation:

Mitosis is a type of cell division in which daughter cell produced are genetically identical to their mother cell. So, no. of chromosome does not change after mitosis.

So, at the end of mitosis, each daughter cell would have <u>20</u> chromosome.

Meiosis is a type of cell division in which mother cell produces two haploid cells ones with a single set of chromosomes.

Meiosis is a two step cell division, Meiosis I and Meiosis II.

In meiosis I, homologous pair separates, so no. of chromosomes becomes half.

In meiosis II, sister chromatids separates. So, the number of chromosomes remains same (i.e. Have same no. of chromosome as present in cell produced after meiosis I).

So, at the end of mitosis, each daughter cell would have <u>20</u> chromosome.

At the end of meiosis I, each daughter cell would have n = 10 chromosomes. At the end of meiosis II, each daughter cell would have n = 10 chromosomes.

7 0
3 years ago
CK-12 Boyle and Charles's Laws if Mrs. Pa pe prepares 12.8 L of laughing gas at 100.0 k Pa and -108 °C and then she force s the
nirvana33 [79]

Answer:

The answer to your question is   P2 = 2676.6 kPa

Explanation:

Data

Volume 1 = V1 = 12.8 L                        Volume 2 = V2 = 855 ml

Temperature 1 = T1 = -108°C               Temperature 2 = 22°C

Pressure 1 = P1 = 100 kPa                    Pressure 2 = P2 =  ?

Process

- To solve this problem use the Combined gas law.

                     P1V1/T1 = P2V2/T2

-Solve for P2

                     P2 = P1V1T2 / T1V2

- Convert temperature to °K

T1 = -108 + 273 = 165°K

T2 = 22 + 273 = 295°K

- Convert volume 2 to liters

                       1000 ml -------------------- 1 l

                         855 ml --------------------  x

                         x = (855 x 1) / 1000

                         x = 0.855 l

-Substitution

                    P2 = (12.8 x 100 x 295) / (165 x 0.855)

-Simplification

                    P2 = 377600 / 141.075

-Result

                   P2 = 2676.6 kPa

3 0
3 years ago
How many hydrogen atoms are attached to each carbon adjacent to a double bond? nurition?
larisa [96]
That depends. there are 2 possible answers.
      H
C - C = C - H gives a different answer on the right than on the left.

One the left side, the second Carbon is attached to a double bond and has but one hydrogen attached to it.

The Carbon on the right of the double bond has 2
     H
C- C = C - H
            H

I'm not sure what you should put. It's one of those things that I would repeat my argument and submit it.
3 0
4 years ago
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