Answer:
I don't really understand the first question but the second question answer is they do not live in the Artic Tundra because they are cold blooded and need hot habitats to survive.
Explanation:
The Arctic Tundra is cold and snakes need warm temps to survive because they are cold blooded.
Answer:
Specific gravity of the sample = 8.947
Explanation:
Specific gravity of a substance is defined as the density of that substance divided by the density of water.
Density of water = 1000g/l
Density of substance = mass/volume
= 85/9.5 x 10^-3
= 8947.37 g/l
SG = 8947.37/1000
= 8.947
Answer:
physical property
Explanation:
it is physical so is any melting and boiling point
Explanation:
The given data is as follows.
Refractive index of mixture = 1.456
Refractive index of hexane = 1.375
Refractive index of toulene = 1.497
Let mole fraction of hexane = 
and, mole fraction of toulene = 
Also, 
or, 
Hence, calculate the mole fraction of hexane as follows.
refractive index mixture= mole fraction hexane × ref index hexane + mole fraction toluene × ref index toluene.
1.456 = 
1.456 = 
0.081 = 
= 
= 0.66
Since,
= 1 - 0.66
= 0.34
Thus, we can conclude that mole fraction of hexane in your sample is 0.34.
Mass after 60 years:
2 kg of cesium-137 will remain after 60.0 years.
What is Half-life?
The duration needed for a quantity to decrease to half of its initial value is known as the half-life.
Given:
N0 = is the initial amount of cesium-137 = 8.0 Kg
N = is the amount remaining after a time = Unknown
t = Duration of cesium-137 decay in 8.0 Kg = 60 years
t1/2 = half-life of cesium-137 = 30.0 years
Formula = N/No = (1/2)^t/t1/2
After putting the value:
N/8= (1/2)^60/30
N/8= (1/2)^2
N/8= 1/4
4N= 8
N= 8/4
N= 2 Kg
As a result, 2 Kg of cesium-137 will be present after 60 years.
Learn more about the half-life here,
brainly.com/question/14018709
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