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MrRissso [65]
3 years ago
12

Calculaye the perimeter and area of these composite shapes

Mathematics
1 answer:
lora16 [44]3 years ago
4 0

For this case we have that the perimeter of the figure is given by the sum of the lengths of the sides, that is:

14 + 18 + 3 + 4 + 3 + 4 + 3 + 4 + (14-9) + (18-12) = 64

Thus, the perimeter of the figure is 64 centimeters.

Now, we find the area of the figure:

We have that by definition, the area of a rectangle is given by:

A = a * b

Where:

a and b are the sides of the rectangle

We have 4 vertical rectangles from left to right:

A_ {1} = 14 * (18-12) = 14 * 6 = 84 \ cm ^ 2\\A_ {2} = (3 + 3 + 3) * 4 = 9 * 4 = 36 \ cm ^ 2\\A_ {3} = (3 + 3) * 4 = 6 * 4 = 24 \ cm ^ 2\\A_ {4} = 3 * 4 = 12 \ cm ^ 2

Thus, the total area isA_ {t} = 156 \ cm ^ 2

Answer:

The perimeter of the figure is 64 centimeters.

A_ {t} = 156 \ cm ^ 2

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Answer:

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Step-by-step explanation:

If we let x = distance batter has run at time t and  D = distance from second base to the batter at  time t, then we know \frac{dx}{dt}=31 ft/s and we want \frac{dD}{dt} when he is halfway (at x = 45).

Using Pythagoras theorem

D^2=90^2+(90-x)^2\\\text{Differentiating with respect to t}\\2D\frac{dD}{dt}=0+2(90-x)(-1)\frac{dx}{dt}\\2D\frac{dD}{dt}=-2(90-x)\frac{dx}{dt}

When x=45

D^2=90^2+(90-x)^2\\D^2=90^2+(90-45)^2\\D^2=10125\\D=\sqrt{10125}

2D\frac{dD}{dt}=-2(90-x)\frac{dx}{dt}\\2\sqrt{10125}\frac{dD}{dt}=-2(90-45)(31)\\\frac{dD}{dt}=\frac{-2(45)(31)}{2\sqrt{10125}} =-13.86ft/s

Thus, when the batter is halfway to first base, the distance between second base and the batter is  decreasing at the rate of about 13.86 ft/sec.

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yKpoI14uk [10]
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Answer:

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Step-by-step explanation:

<u>The absolute value function is:</u>

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<u>Step 2. Shifted two units left:</u>

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<em>See attached</em>

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dimaraw [331]
Answer:
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Solution:
Make algebraic equation to solve
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Answer: Hope This Helps!

Step-by-step explanation:

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