Velocity=3.4m/sec
Mass=30kg
so kinetic energy=1/2mv^2
=1/2×30×3.4×3.4
=15×3.4×3.4
=15×11.56
=173.4 kg m per second square
Refer to the diagram shown below.
Assume that air resistance is ignored.
Note:
The distance, h, of a falling object with initial vertical velocity of zero at time t is
h = (1/2)gt²
where
g = 9.8 m/s²
The initial vertical velocity of the supplies is 0 m/s.
It the time taken for the supplies to reach the ground is t, then
(50 m) = (1/2)*(9.8 m/s²)*(t s)²
Hence obtain
t² = 50/4.9 = 10.2041
t = 3.1944 s
The horizontal distance traveled at a speed of 100 m/s is
d = (100 m/s)*(3.1944 s) = 319.44 m
Answer: 319.4 m (nearest tenth)
Answer:
Torque = R X F = R * F sin theta
-f * 2R will exert an equal opposite torque
-f * 2 = F sin theta
f = -F sin theta / 2
In the modern model of the atoms over 99.9℅ of the atom is made up of empty space
Answer:


Explanation:
v = Velocity of the elevator = 3.1 m/s
= Angle of the slope = 
Vertical component is given by

The vertical component of the velocity is
.
Horizontal component is given by

The horizontal component of the velocity is
.