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3 years ago

10

Consider the following statement:

1 answer:

ra1l [238]3 years ago

5 0

Answer:

Because the Magnetic Field lines are closed- we need to express, which area of the space is considered for the given direction

Explanation:

The magnetic field lines have enclosed nature- they do look like a circle. Once we consider a permanent magnet with the north and south pole, in the area outside from the magnet, lines go from the North towards the South pole, where they enter the magnet. However, inside the magnet, these lines have direction from the south to the north pole to close the ends of the line. So, once we consider the directions of the magnetic field inside the magnet, the given statement is not correct.

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Q30. When working near some large air cored inductors you misplace a socket and as you cannot find it you

Andre45 [30]

When the piece of metal blundered into the air-core coil, it changed the inductance of the coil.

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3 years ago

A solid is 4 cm tall,5 cm wide and 3 cm thick.it has a density of 5.2g/cm^3.what is its mass?

zhenek [66]

Explanation:

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3 years ago

The Moon is visible to observers on Earth because of

expeople1 [14]

A. Reflected sunlight

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3 years ago

Read 2 more answers

Suppose the maximum safe intensity of microwaves for human exposure is taken to be 1.00 W/m2 . (a) If a radar unit leaks 10.0 W

storchak [24]

Answer:

We must be approximately at least 1.337 meters away to be exposed to an intensity considered to be safe.

Explanation:

Let suppose that intensity is distributed uniformly in a spherical configuration. By dimensional analysis, we get that intensity is defined by:

$I = \frac{\dot W}{\frac{4\pi}{3}\cdot r^{3}}$ (1)

Where:

$I$ - Intensity, measured in watts per square meter.

$r$ - Radius, measured in meters.

If we know that $\dot W = 10\,W$ and $I = 1\,\frac{W}{m^{2}}$ , then the radius is:

$r^{3} = \frac{\dot W}{\frac{4\pi}{3}\cdot I }$

$r = \sqrt[3]{\frac{3\cdot \dot W}{4\pi\cdot I} }$

$r = \sqrt[3]{\frac{3\cdot (10\,W)}{4\pi\cdot \left(1\,\frac{W}{m^{2}} \right)} }$

$r \approx 1.337\,m$

We must be approximately at least 1.337 meters away to be exposed to an intensity considered to be safe.

5 0

3 years ago

Unpolarized light enters a polarizer with vertical polarization axis. The light that passes through passes another polarizer wit

mylen [45]

Answer:

I = 0.2934 I₀

Explanation:

The expression that governs the transmission of polarization is

I = I₀ cos² θ

Let's apply this to our case, when the unpolarized light enters the first polarized, the polarized light that comes out has the intensity of

I₁ = I₀ / 2

this is the light that enters the second polarizer

I = I₁ cos² θ

we substitute

I = I₀ / 2 cos² 40

I = I₀ 0.2934

I = 0.2934 I₀

4 0

4 years ago