All categories

3 years ago

Which element has the electron configuration 2-4?

Chemistry

1 answer:

denpristay [2]3 years ago

4 0

Carbon has the electronic configuration 2,4

You might be interested in

The substance that is doing the dissolving is referred to as?

ella [17]

Answer:

hi! I'm pretty sure your answer is solvent!

Explanation:

not 100% sure but I looked it up on google. solvent does the dissolving, solute is what is being dissolved, and a solution is the solvent + the solute. hope this helped!

7 0

4 years ago

Using a graduated cylinder, fill a 600 mL beaker with 100 mL of water.

fomenos

Answer:

Temperature of water: 3

Reaction time: 138.5

Explanation:

Your welcome

5 0

4 years ago

Read 2 more answers

What formula is MaVa=MbVb?

yawa3891 [41]

I don't know if this helps...but it is a titration formula.

5 0

4 years ago

Nuclear power plants use uranium, a nonrenwable resource, for fuel

Crazy boy [7]

True. Although nuclear energy itself is renewable, the material (uranium) used in nuclear power plants is not.

7 0

3 years ago

How many total ions are in 2.95 g of magnesium sulfite?

Aleksandr [31]

Answer:

Approximately $5.65 \times 10^{-2}\; \rm mol$ , which is approximately $3.41 \times 10^{22}$ particles.

Explanation:

Formula of magnesium sulfite: $\rm MgSO_3$ .

Look up the relative atomic mass of $\rm Mg$ . $\rm S$ , and $\rm O$ on a modern periodic table:

$\rm Mg$ : $24.305$ .
$\rm S$ : $32.06$ .
$\rm O$ : $15.999$ .

The ionic compound $\rm MgSO_3$ consist of magnesium ions $\rm {Mg}^{2+}$ and sulfite ions $\rm {SO_3}^{2-}$ .

Notice that $\rm {Mg}^{2+}\!$ and $\rm {SO_3}^{2-}\!$ combine at a one-to-one ratio to form the neural compound $\rm MgSO_3$ . Therefore, each $\rm MgSO_3\!$ formula unit would include one $\rm {Mg}^{2+}$ ion and one $\rm {SO_3}^{2-}$ ion (that would be two ions in total).

Calculate the formula mass of one such formula unit:

$\begin{aligned}&\; M(\mathrm{MgSO_3}) \\ = & \; 24.305 + 32.06 + 3 \times 15.999 \\ = & \; 104.362\; \rm g \cdot mol^{-1}\end{aligned}$ .

In other words, the mass of one mole of $\rm MgSO_3$ formula units (which includes one mole of $\rm {Mg}^{2+}$ ions and one mole of $\rm {SO_3}^{2-}$ ions) would be $104.362\; \rm g$ .

Calculate the number of moles of such formula units in that $2.95\; \rm g$ of $\rm MgSO_3$ :

$\begin{aligned}n&= \frac{m}{M}\\ &=\frac{2.95\; \rm g}{104.362\; \rm g \cdot mol^{-1}} \approx 2.82670 \times 10^{-2}\; \rm mol\end{aligned}$ .

There are two moles of ions in each mole of $\rm MgSO_3$ formula units. Therefore, that $2.82670 \times 10^{-2}\; \rm mol$ of $\rm MgSO_3\!$ formula units would include approximately $2 \times 2.82670 \times 10^{-2}\; \rm mol \approx 5.65\times 10^{-2}\; \rm mol$ of ions.

8 0

3 years ago