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lubasha [3.4K]
2 years ago
10

Please help me, I really need it, God Bless you <3

Chemistry
1 answer:
gladu [14]2 years ago
7 0

#1

\\ \sf\longmapsto {}^{88}_{38}Sr^{2+}

  • As 2 electrons are donated Hence the No of electrons =38-2=36

#2

\\ \sf\longmapsto {}^{51}_{23}V^{3+}

  • As 3 electrons donated the no of electrons=23-3=20

#3

\\ \sf\longmapsto {}^{55}_{26}Fe^{3+}

  • No of neutrons=55-26=29

#4

\\ \sf\longmapsto {}^{112}_{48}

  • As 2 electrons are donated no of electrons =48-2=46

#5

\\ \sf\longmapsto {}^{210}_{82}Pb^{2+}

  • No of neutrons=210-82=128
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Answer:

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The reaction of HCl with NaOH is:

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The end point was reached when the student added:

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The volume of the sample of hydrochloric acid was 20.0mL = 0.0200L, and concentration of the sample is:

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