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Aleksandr-060686 [28]
2 years ago
9

A sample of aluminum is placed in a 25 ml graduated cylinder containing 10 mL of water. The level of water rises to 18 mL. Alumi

num has a density of 2.7 g/mL. Calculate the mass of the sample
Please include explanation if possible
Chemistry
2 answers:
Readme [11.4K]2 years ago
8 0

Answer: The mass of sample is 21.6 grams.

Explanation:

We are given:

Volume of cylinder without object, V_1 = 10 mL

Volume of cylinder with object, V_2 = 18 mL

Volume of object = V_2-V_1=18-10=8mL

To calculate volume of a substance, we use the equation:

\text{Density of a substance}=\frac{\text{Mass of a substance}}{\text{Volume of a substance}}

We are given:

Density of sample (aluminum) = 2.7 g/mL

Volume of sample (aluminum) = 8 mL

Putting values in above equation, we get:

2.7g/mL=\frac{\text{Mass of a sample}}{8mL}\\\\\text{Mass of object}=21.6g

Hence, the mass of sample is 21.6 grams.

anastassius [24]2 years ago
4 0

To determine the mass of the sample, first find the volume difference after and before the aluminum was placed, the volume change is equal to the volume of the submerged object, in this case aluminum.

Then knowing volume of aluminum and the density of it, we can solve for the mass.

D = m/v

Dv = m

2.7 g/ml • 8 ml = 21.6 grams.

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Studentka2010 [4]

Answer:

To supply the required ions it is necessary to inject 5,6mL of 6g/30mL solution and 131,1 mL of 0,9% solution.

Explanation:

1mEq of sodium are 59mg of NaCl and 1mEq of potassium are 75mg KCl

in intravenous infusion 15 mEq of K are:

15x75mg KCl = 1,125g of KCl

And 20 mEq of Na are:

20x59mg NaCl = 1,18g of NaCl

To supply the potassium ion it is necessary to inject:

1,125g of KCl×\frac{30mL}{6g} =<em> 5,6mL  of 6g/30mL solution</em>

And, to supply the sodium ion it is necessary to inject:

1,18g of NaCl×\frac{100mL}{0,9g} = <em>131,1 mL of 0,9% solution</em>

<em />

I hope it helps!

6 0
3 years ago
A crystallographer measures the horizontal spacing between molecules in a crystal. The spacing is
erastova [34]

Answer: The total width of a crystal is 1.65 mm.

Explanation:

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Width of the 10^5 molecules :16.5 nm\times 10^5=16.5\times 10^5 nm

1 nm=10^{-6} mm

The total width of a crystal in millimeter=16.5\times 10^5\times 10^{-6} mm=1.65 mm

The total width of a crystal is 1.65 mm.

7 0
3 years ago
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Answer:

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This electron withdrawal by resonance makes the pyridine ring less electron rich or more electron deficient.

Hence, the nitro group makes the pyrinde ring more electron deficient

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