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timurjin [86]
3 years ago
8

"a gaseous mixture contains 414.0 torr of h2(g), 345.7 torr of n2(g), and 80.1 torr of ar(g). calculate the mole fraction, x, of

each of these gases."
Chemistry
1 answer:
DENIUS [597]3 years ago
7 0
<span>The gaseous mixture contains 414.0 torr of h2(g), 345.7 torr of n2(g), and 80.1 torr of ar(g). Then, total pressure of the gas would be: 414 torr + 345.7 torr + 80.1 torr= 839.8 torr
The mole fraction of each gas:
H2= 414 torr/</span>839.8 torr= 0.49
N2= 345.7 torr/839.8 torr= 0.41
Ar= 80.1 torr/839.8 torr= 0.10

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Two solutions are created by mixing one solution containing lithium nitrate with one containing sodium phosphate.
babunello [35]

Answer:

Solution A that will form a precipitate with Ksp = 2.3 x 10−4

Explanation:

                                  Li₃PO₄ ⇄ 3 Li⁺(aq) + PO₄³⁻(aq)

                                                     3S               S

Where S = Solubility(mole/lit) and Ksp = Solubility product

⇒ Ksp = (3S)³ x (S)

⇒ 27S⁴ = 2.3x10−4

⇒ S = 0.05 mol/lit

Concentration of Li₃PO₄ precipitate = 0.05

<u>Solution A </u>

0.500 lit of a 0.3 molar LiNO₃ contains 0.5 x 0.3 = 0.15 mole

0.4 lit of a 0.2 molar Na₃PO₄ contains = 3 x 0.4 x 0.2 = 0.24 mole

                                     3 LiNO₃ + Na₃PO₄ → 3 NaNO₃ + Li₃PO₄

(Mole/Stoichiometry)    \frac{0.15}{3}                \frac{0.24}{1}

                                   = 0.05            = 0.24

Since from (Mole/Stoichiometry) ratio we can conclude that LiNO₃ is limiting reagent.

So concentration of Li₃PO₄ is equal to 0.05.

                       

6 0
2 years ago
What would you observe in the reaction of calcium with nitric acid​
Marina CMI [18]

Answer:

reacts to form carbondioxide

6 0
3 years ago
. Using the pH scale below what would be the pH value of an Acid? *
earnstyle [38]

Answer : The pH value of an acid is below 7.

Explanation :

pH : It is defined as the negative logarithm of hydrogen ion or hydronium ion concentration.

Mathematically,

pH=-\log [H^+]

When the pH less than 7 then the solution is acidic and the concentration of hydrogen ion is greater than hydroxide ion.

When the pH more than 7 then the solution is basic and the concentration of hydrogen ion is less than hydroxide ion.

When the pH is equal to 7 then the solution is neutral and the concentration of hydrogen ion is equal to the hydroxide ion.

Hence, the pH value of an acid is below 7.

6 0
3 years ago
You are given two unknown acids, HX and H2Y, and two values for Ka, 1x10^-7 and 1x10^9. You know that X is a much more electrone
Elena L [17]

Answer:

.

Explanation

In HX , X is more electronegative than Y so HX will ionise more because of  ionic bond between H and X . On the other hand H₂Y will be less polar as compared to HX so it will ionise to a lesser extent . Hence Ka will be more for HX . Ka represents the degree of ionisation of acid . Higher the ionisation , higher is the value of Ka . H₂Y which is less polar will ionise less and hence it will have lesser value of Ka .

Hence H₂Y will have value of 10⁻⁷ and HX will have value of ka equal to 10⁹ .

6 0
3 years ago
A large highway barrier is 1 meter wide, by 1 meter tall, by 2 meters long.
Romashka [77]

Answer:

when mass is  1×10⁴ Kg then density is 5 g/cm³.

when mass is 104 Kg then density is 5.2 × 10⁻² g/ cm³.

Explanation:

Density:

Density is equal to the mass of substance divided by its volume.

Units:

SI unit of density is Kg/m3.

Other units are given below,

g/cm3, g/mL , kg/L

Formula:

D=m/v

D= density

m=mass

V=volume

Symbol:

The symbol used for density is called rho. It is represented by ρ. However letter D can also be used to represent the density.

Given data:

mass = 1×10⁴ Kg

volume= w ×l× h = 1×2× 1 = 2 m³

density = ?

first of all we will convert the given volume meter cube to cm³:

we know that  

2×1000000 = 2 × 10⁶ cm³

Now we will convert the mass into gram.

1 Kg = 1000 g

1×10⁴ × 1000 = 1 ×10⁷ g

Now we will put the values in the formula,

d = m/v

d = 1 ×10⁷ g / 2×10⁶ cm³

d = 0.5 × 10¹ g/cm³

   or

d = 5 g/cm³

If mas is 104 Kg:

104 × 1000 = 104000 g

d= m/v

d = 104000 g / 2×10⁶ cm³

d= 52000 ×10⁻⁶ g/ cm³

d= 5.2 × 10⁻² g/ cm³

7 0
3 years ago
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